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Serhud [2]
2 years ago
10

orange light has a wavelength, λ, of 6.0 × 10-7 m. in a vacuum, the speed of light, c, is 3.0 × 108 m/s. what is the frequency,

f, of the orange light? (remember: 1 hz
Physics
1 answer:
PolarNik [594]2 years ago
3 0

The frequency of orange light is 5 x 10¹⁴ Hz or 500 THz.

We need to know about photon frequency to solve this problem. The photon frequency can be determined as

f = c / λ

where f  is frequency, c is speed of light (3x10⁸ m/s) and λ is wavelength.

From the question above, we know that:

c = 3x10⁸ m/s

λ = 6 x 10¯⁷ m

By substituting parameters, we get

f = c / λ

f =  3 x 10⁸ /( 6 x 10¯⁷ )

f = 5 x 10¹⁴ Hz

For more on frequency at: brainly.com/question/10728818

#SPJ4

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You are pulling a child in a wagon. The rope handle is inclined upward at a 60∘ angle. The tension in the handle is 20 N.
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If temperature increases, then pressure __________.
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Our milky way galaxy is 100000 lyly in diameter. a spaceship crossing the galaxy measures the galaxy's diameter to be a mere 1.
Sidana [21]

The speed of the spaceship relative to the galaxy is 0.99999995c.

A light-year measures distance rather than time (as the name might imply). A light-year is a distance a light beam travels in one year on Earth, which is roughly 6 trillion miles (9.7 trillion kilometers). One light-year equals 5,878,625,370,000 miles. Light moves at a speed of 670,616,629 mph (1,079,252,849 km/h) in a vacuum.We multiply this speed by the number of hours in a year to calculate the distance of a light-year (8,766).

The Milky way galaxy is 100,000 light years in diameter.

The galaxy's diameter is a mere 1. 0 ly.

We know that ;

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L = 1 light year

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1 = 100,000 \sqrt{1-\frac{v^2}{c^2} }

1 = 100,000 \sqrt{1-\frac{v^2}{(3*10^8)^2} }

\frac{1}{100,000}  = \sqrt{1-\frac{v^2}{c^2} }

v = 0.999999995 c

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Learn more about a light year here:

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