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klio [65]
3 years ago
14

Find 3 consecutive odd integers with a sum of 63. PLEASE HELP!!!​

Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
6 0

Answer:

the numbers are 20, 21 and 22

Step-by-step explanation:

x+(x+1) + (x+2) = 63

3x +3 = 63

3x = 60

x = 20

mamaluj [8]3 years ago
4 0

Answer:

the numbers are 20, 21 and 22

Step-by-step explanation:

x+(x+1) + (x+2) = 63

3x +3 = 63

3x = 60

x = 20

doing this for ponits

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What should the first step be when solving for x?<br>-5x+6(-2x-13)=7​
Juli2301 [7.4K]

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multiply the things in the () with6

Step-by-step explanation:

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2 years ago
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Kyle is painting the front door of his house. The dimensions of the door are 80 inches by 36 inches by 2 inches. If he paints al
kolbaska11 [484]

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its 5760ins

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80 inches * 36 inches * 2 inches = 5760 inches3

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3 years ago
Find the value of x need help asap
oee [108]

Answer:

B

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5 0
3 years ago
In a video game, Agnes scored 20% fewer than Amy. Amy scored 860
vovangra [49]

Answer:

\huge\boxed{\sf Agnes\ Score = 688\ points}

Step-by-step explanation:

\sf = 20 \% \ of \ 860 \\\\= \frac{20}{100} * 860\\\\= 2 * 86\\\\= 172 \ points

Since, Agnes scored 20 % fever than Amy.

So,

Agnes Score = Amy's Points - 20 % of Amy's Points

Agnes Score = 860 - 172

Agnes Score = 688 points

\rule[225]{225}{2}

Hope this helped!

<h3>~AnonymousHelper1807</h3>
8 0
3 years ago
How many 10-digit ternary strings are there that contain exactly two 0s, three 1s, and five 2s?
Svet_ta [14]

There are \dbinom{10}2 ways of picking 2 of the 10 available positions for a 0. 8 positions remain.

There are \dbinom83 ways of picking 3 of the 8 available positions for a 1. 5 positions remain, but we're filling all of them with 2s, and there's \dbinom55=1 way of doing that.

So we have

\dbinom{10}2\dbinom83\dbinom55=\dfrac{10!}{2!(10-2)!}\dfrac{8!}{3!(8-3)!}\dfrac{5!}{5!(5-5)!}=2520

The last expression has a more compact form in terms of the so-called multinomial coefficient,

\dbinom{10}{2,3,5}=\dfrac{10!}{2!3!5!}=2520

5 0
3 years ago
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