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klio [65]
3 years ago
14

Find 3 consecutive odd integers with a sum of 63. PLEASE HELP!!!​

Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
6 0

Answer:

the numbers are 20, 21 and 22

Step-by-step explanation:

x+(x+1) + (x+2) = 63

3x +3 = 63

3x = 60

x = 20

mamaluj [8]3 years ago
4 0

Answer:

the numbers are 20, 21 and 22

Step-by-step explanation:

x+(x+1) + (x+2) = 63

3x +3 = 63

3x = 60

x = 20

doing this for ponits

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Answer:

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One solution: 7−5+3x−1= 2x + 4

Infinitely Many Solutions  7−5+3x−1= 3x + 1

Step-by-step explanation:

No solutions means it results in no x and a false statement like 3 = 0.

One solution means it results in x = a number.

Infinite solutions means its results in no x and in a true statement like 3=3.

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This will eliminate the x and result in 1 = 7 which is false.

  • One solution: 7−5+3x−1= 2x + 4

This will result in x= 3

  • Infinitely Many Solutions  7−5+3x−1= 3x + 1

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males = 7x + 1 = 7(7) + 1 = 49 + 1 = 50
females = (7x+1)/2 = 50/2 = 25

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Step-by-step explanation:

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