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<u>Given:</u>
Moles of He = 15
Moles of N2 = 5
Pressure (P) = 1.01 atm
Temperature (T) = 300 K
<u>To determine:</u>
The volume (V) of the balloon
<u>Explanation:</u>
From the ideal gas law:
PV = nRT
where P = pressure of the gas
V = volume
n = number of moles of the gas
T = temperature
R = gas constant = 0.0821 L-atm/mol-K
In this case we have:-
n(total) = 15 + 5 = 20 moles
P = 1.01 atm and T = 300K
V = nRT/P = 20 moles * 0.0821 L-atm/mol-K * 300 K/1.01 atm = 487.7 L
Ans: Volume of the balloon is around 488 L
Answer:
Concept: Chemical Analysis
- Start by taking inventory of the elements that you have
- Make a list, one for the right side and another for the left side
- Then add coefficients to the elements to the right or left side to balance out the equation
The answer is 27 grams. Hope it helps
(1,0)n +(235,92)U --->(91,36)Kr + (142,56) Ba + 3(1,0)n
