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3 years ago

What is pH?

1 answer:

5 0

PH = -log[H+]
That is, pH is the negative logarithm of the hydrogen ion concentration.

pOH = -log[OH-]
pOH is the negative logarithm of the hydroxide ion concentration.

The correct answer to your question is a. The negative logarithm of the hydrogen ion concentration.

You might be interested in

What geological process(es) could form magnesium silicate perovskite at 500 C?

dimulka [17.4K]

Magnesium silicate is a compound of magnesium oxide and silicon. It is the magnesium salt of silicic acid containing an unspecified amount of water. The molecular formula can be expressed more clearly as MgSiO3.

7 0

2 years ago

You have 16.0 g of some compound and you perform an experiment to remove all of the oxygen, 11.2 g of iron is left. What is the

oksian1 [2.3K]

The empirical formula of this compound is equal to $Fe_{2}O_3$ .

<h3>Empirical formula</h3>

To calculate the empirical formula of a compound, it is necessary to know the number of moles present.

Therefore, we will use the molar mass of iron and oxygen to find the amount of moles, so that:

$MM_O = 16g/mol\\MM_Fe = 55.8g/mol$

$MM = \frac{m}{mol}$

Oxygen

$16 = \frac{4.8}{mol}$

$mol = 0.3$

Iron

$55.8 = \frac{11.2}{mol}$

$mol = 0.2$

Finally, as the empirical formula is composed of integers numbers of moles, just multiply the values by the smallest common factor to transform into an integer, so that:

O => $0.3 \times 10 = 3moles$

Fe => $0.2 \times 10 = 2moles$

So, the empirical formula of this compound is equal to $Fe_{2}O_3$

Learn more about empirical formula in: brainly.com/question/1363167

6 0

3 years ago

Air, with an initial absolute humidity of 0.016 kg water per kg dry air, is to be dehumidified for a drying process by an air co

amid [387]

Answer:

(a) The proportion of dry air bypassing the unit is 14.3%.

(b) The mass of water removed is 1.2 kg per 100 kg of dry air.

Explanation:

We can express the proportion of air that goes trough the air conditioning unit as $p_{d}$ and the proportion of air that is by-passed as $p_{bp}$ , being $p_{d}+p_{bp}=1$ .

The amount of water that goes into the drier inlet has to be 0.004 kg/kg, and can be expressed as:

$0.004 = 0.016*p_{bp}+ 0.002*p_{d}$

Replacing the first equation in the second one we have

$0.004 = 0.016*(1-p_{d})+ 0.002*p_{d}=0.016-0.016*p_{d}+0.002*p_{d}\\0.004 - 0.016 = (-0.016+0.002)*p_{d}\\-0.012 = -0.014*p_{d}\\p_{d}=\frac{-0.012}{-0.014}=0.857\\\\p_{bp}=1-p_{d}=1-0.857=0.143$

(b) Of every kg of dry air feed, 85.7% goes in to the air conditioning unit.

It takes (0.016-0.002)=0.014 kg water per kg dry air feeded.

The water removed of every 100 kg of dry air is

$100 kgDA*0.857*0.014 kgW/kgDA= 1.1998 \approx 1.2 kgW$

It can also be calculated as the difference in humiditiy between the inlet and the outlet: (0.016-0.004=0.012 kgW/kDA) and multypling by the total amount of feed (100 kgDA).

100 * 0.012 = 1.2 kgW

7 0

4 years ago

Highlighted answer is wrong just need someone to explain it if you can!❤️

lora16 [44]

Answer:

2.7 x 10^-1

Explanation:

The places you move to the left are added to the 10 in negative exponential

7 0

3 years ago

Suppose a sodium hydroxide solution was standardized against pure solid primary standard grade KHP. If 0.4798 g of KHP required

Readme [11.4K]

Answer:

The NaOH solution has a molarity of 0.052 M

Explanation:

<u>Step 1:</u> Data given

Mass of KHP = 0.4798 grams

Volume of NaOH= 45.22 mL = 0.04522 L

Molar mass of NaOH = 40 g/mol

Molar mass of KHP = 204.22 g/mol

<u>Step 2</u>: Calculate moles of KHP

Moles KHP = mass KHP / Molar mass KHP

Moles KHP = 0.4798 grams / 204.22 g/mol

Moles KHP = 0.00235 moles

<u>Step 3</u>: Calculate moles of NaOH

KHP here acts as a mono-acid so, the number of moles of NaOH = number of moles KHP = 0.00235 moles

<u>Step 4: </u>Calculate molarity of NaOH

Molarity NaOH = moles NaOH / volume NaOH

Molarity NaOH = 0.00235 moles / 0.04522 L

Molarity NaOH = 0.052 M

The NaOH solution has a molarity of 0.052 M

6 0

4 years ago