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Vlad1618 [11]
2 years ago
13

the difference in energy between the n=1 and n=2 energy levels in a hydrogen atom is 1.64x10^-18 J. what happens when an electro

n in a hydrogen atom transitions from n=2 to n=1?
Chemistry
1 answer:
CaHeK987 [17]2 years ago
6 0

Answer:

It emits 1.64 x 10⁻¹⁸J of energy

Explanation:

The n = 1 is a lower quantum level compared to n = 2.

When a hydrogen atom moves from a higher level to a lower one, it simply emits the energy difference between the two levels.

  • If a hydrogen atom moves from a lower energy level to a higher one such as from 1 to 2, they absorb the energy difference to attain the new excited state.
  • So, for an electron in the hydrogen atom to move from a higher energy level to a lower one, it must emit 1.64 x 10⁻¹⁸J of energy.
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A solution is made by dissolving 4.87 g of potassium nitrate in water to a final volume of 86.4 mL solution. What is the weight/
lara31 [8.8K]

Answer:

A solution is made by dissolving 4.87 g of potassium nitrate in water to a final volume of 86.4 mL solution. The weight/weight % or percent by mass of the solute is :

<u>2.67%</u>

Explanation:

Note : Look at the density of potassium nitrate in water if given in the question.

<u><em>You are calculating </em></u><u><em>weight /Volume</em></u><u><em> not weight/weight % or percent by mass of the solute</em></u>

Here the <u>weight/weight % or percent by mass</u> of the solute is asked : So first convert the<u> VOLUME OF SOLUTION into MASS</u>

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density=\frac{mass}{volume}

Density = 2.11 g/mL

Volume of solution = 86.4 mL

2.11=\frac{mass}{86.4}

mass = 2.11\times 86.4

mass=182.3grams

Mass of Solute = 4.87 g

Mass of Solution = 183.2 g

w/w% of the solute =

= \frac{mass\ of\ solute}{mass\ of\ solution}\times 100

=\frac{4.87}{183.2}\times 100

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8 0
3 years ago
Cyclopropane is more reactive than most cycloalkanes. What factors lead to cyclopropane being less stable than the other cycloal
maw [93]

Answer: The factor that lead to cyclopropane being less stable than the other cycloalkanes is the presence of a RING STRAIN.

Explanation:

In organic chemistry, the end carbon atoms of an open aliphatic chain can join together to form a closed system or ring to form cycloalkanes. Such compounds are known as cyclic compounds. Examples include cyclopropane, cyclobutane, cyclopentane and many among others.

Cyclopropane is less stable than other cycloalkanes mentioned above because of the presence of ring strain in its structural arrangement. The ring strain is the spatial orientation of atoms of the cycloalkane compounds which tend to give off a very high and non favourable energy. The release of heat energy which is stored in the bonds and molecules cause the ring to be UNSTABLE and REACTIVE.

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8 0
2 years ago
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alexira [117]

Answer:

We'll have 1 mol Al2O3 and 3 moles H2

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Step 3: Calculate the limiting reactant

For 2 moles Al we need 3 moles H2O to produce 1 mol Al2O3 and 3 moles H2

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Step 4: Calculate moles products

For 2 moles Al we need 3 moles H2O to produce 1 mol Al2O3 and 3 moles H2

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For 2 moles Al We'll have 3/2 * 2 = 3 moles H2

We'll have 1 mol Al2O3 and 3 moles H2

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