Answer:
v = 45.37 m/s
Explanation:
Given,
angle of inclination = 8.0°
Vertical height, H = 105 m
Initial K.E. = 0 J
Initial P.E. = m g H
Final PE = 0 J
Final KE = 
Using Conservation of energy
v = 45.37 m/s
Hence, speed of the skier at the bottom is equal to v = 45.37 m/s
Answer:
B) x^2+6x+8
Explanation:
x-4 | x^3+2x^2-16x-32
- x^3-4x^2 <-- (x-4)(x^2)
_________________
6x^2-16x-32
- 6x^2-24x <-- (x-4)(6x)
_________________
8x-32
- 8x-32 <- (x-4)(8)
___________________________
0 | x^2+6x+8
This means the answer is B) x^2+6x+8
Answer:
80 ft/s
Explanation:
Use III equation of motion
V^2 = U^2 + 2g h
Here, U = 0, g = 32 ft/s^2, h = 100 ft
V^2 = 0 + 2 × 32 ×100
V^2 = 6400
V = 80 ft/s
Answer:
C. 14400
Explanation:
40min × 6 periods = 240mins total.
1 minute = 60 seconds.
240 minutes × 60 = 14400 seconds.
Work = Force* Distance
2000*1000=2000000
Power = Work/Time
2000000/45=<span>44444.44 Watts</span>
