What is net force? A. The fundamental forces B. The unified force C. The gravitational force D. The vector sum of the forces

Physics

2 answers:

avanturin [10]3 years ago

8 0

It is the vector sum of the forces

dedylja [7]3 years ago

7 0

Net force is the vector sum of the forces.

Answer: Option D

<u>Explanation:</u>

The net force can be referred as the sum total of all the forces exerted up on a body. The word net refers to the total, hence net force refers to the total force which exerted upon the object.

A force is related as the displacement experienced by an object due to external factors or interaction acting up on the object. Option A,B and C are irrelevant as they are separate forces exerted up on the object.

You might be interested in

The conversion of thermal energy into mechanical energy requires

emmainna [20.7K]

Temperature difference is required, so i’m guessing - a. thermometer - would be required to check that temperature.

8 0

2 years ago

How do I write an essay on how I feel about online school

vlabodo [156]

Answer:

Some students appreciated the social aspect of Zoom classrooms, while others felt online education worked best for them when they were working on their own. ... Students said they appreciated having a well-planned work week and didn't appreciate “surprise” assignments online any more than they appreciate them in class

Explanation:

What's I know I said

What do you u write it

5 0

3 years ago

A dolphin in an aquatic show jumps straight up out of the water at a velocity of 13.0 m/s.

SVEN [57.7K]

Answer:

a) Knowns, initial speed $v_{i}=13.0 m/s$ , final speed $v_{f}=0 m/s$ and gravity due it is a constant $g=9.8m/s^{2}$

b) The maximum high reached by the dolphin is $y_{max}=8.62 m$

c) Total time is $t=2.65s$

Explanation:

a) First of all the initial speed is given at the start of the problem, gravity is constant and final speed is known any object thrown straight up reaches its max high at $0m/s$ speed.

b) Second, now that we know final speed we use $v_{f} =v_{i}-gt$ , as we clear for $t=\frac{v_{i}-v_{f} }{g}=\frac{20.0m/s}{9.8m/s^{2} }=1.32 s$ .

Then we use $y=v_{i}t-\frac{1}{2} gt^{2}=(20.0m/s)(1.32s)-\frac{1}{2} (9.8m/s^{2} ) (1.32s)^{2} =8.62m$

c)Third, finally we can use $y=v_{i}t-\frac{1}{2} gt^{2}$ , as we know $y=0m$ when the dolphin fall into the water again and $v_{i} =13.0m/s$ , then we have $0=(13m/s)t-\frac{1}{2} (9.8m/s^{2} )t^{2}$ is a quadratic form $0=t(13.0-4.9t)$ so we have $t_{i}=0s$ and $t_{f}=\frac{13}{4.90} =2.65s$