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Naddik [55]
3 years ago
13

An isotope has 46 electrons, 60 neutrons, and 46 protons. Name the isotope.

Physics
2 answers:
gavmur [86]3 years ago
7 0

Answer:

palladium-106

Explanation:

46 protons -46 electrons=no charge

46 electrons +60neutron = 106

Thus this is called palladium -106

Olegator [25]3 years ago
3 0

Answer:

Palladium

Explanation:

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Waves with higher amplitude transfer ____energy.
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Answer:

- Waves with higher amplitude transfer HIGHER energy.

- Waves with higher frequency transfer HIGHER energy.

3 0
3 years ago
Explain the range of effectiveness of each fundamental force by describing the distance that each force influence nearby matter
Bas_tet [7]

Answer:

Actually, gravity is the weakest of the four fundamental forces. Ordered from strongest to weakest, the forces are 1) the strong nuclear force, 2) the electromagnetic force, 3) the weak nuclear force, and 4) gravity.

6 0
3 years ago
The value of acceleration due to gravity is less at the top of Mount Everest then that in the terai reason, why?​
xxTIMURxx [149]

Answer:

The value of acceleration due to gravity is greater in terai than in mountain. In terai region the radius of earth is less as it lies close to the centre of the earth. Thus, the value of g is more in terai region.

3 0
3 years ago
A fast-food restaurant uses a conveyor belt to send the burgers through a grilling machine. if the grilling machine is 1.2 m lon
Vinil7 [7]

length of the grilling machine is 1.2 m

time taken to cook the burger is 2.7 min = 162 s

so the speed of the machine should be like this that if must have to cook till it cross the machine

v = \frac{d}{t}

v = \frac{1.2}{162}

v = 7.41* 10^{-3} m/s

now in one minute the total length of the machine that is covered is given by

L = v*t

L = 7.41*10^{-3}* 60 = 44.4 cm

now distance between the burgers is 15 cm

so total production rate will be

N = \frac{44.4}{15} = 3 burger/min

so it will produce 3 burger per minute

8 0
3 years ago
Two charges, X and Y, are placed along the x-axis. Charge X is +18 nC and is placed at x = 0. Charge Y is placed at a location o
Helen [10]

Answer:

Charge Z can be placed at <em>x</em> = -2.7 m or at <em>x</em> = 0.27 m.

Explanation:

The Coulomb force between two charges, Q_1 and Q_2, separated by a distance, d, is given

F = k\dfrac{Q_1Q_2}{r^2}

<em>k</em> is a constant.

For the charge Z to be at equilibrium, the force exerted on it by charge X must be equal and opposite to the force exerted on it by charge Y.

It is to be placed along the <em>x</em>-axis. Hence, it is on the same line as charges X and Y.

Let the charge on Z be <em>Q</em>. It is positive.

Let the distance from charge X be <em>x m.</em> Then the distance from charge Y will be (0.60 - <em>x</em>) m.

Force due to charge X

F_X = k\dfrac{18Q}{x^2}

Force due to charge Y

F_Y = k\dfrac{-27Q}{(0.60-x)^2}

Since both forces are equal and opposite,

F_X = -F_Y

k\dfrac{18Q}{x^2} = -k\dfrac{-27Q}{(0.60-x)^2}

\dfrac{2}{x^2} = \dfrac{3}{(0.60-x)^2}

2(0.60-x)^2 = 3x^2

2(0.36-1.20x+x^2) = 3x^2

0.72-2.40x+2x^2 = 3x^2

x^2+2.40x-0.72 = 0

Applying the quadratic formula,

x = \dfrac{-2.40\pm\sqrt{2.40^2 - (4)(1)(-0.72)}}{2} = \dfrac{-2.40\pm\sqrt{8.64}}{2}

x = -2.7 or x = 0.27

Charge Z can be placed at <em>x</em> = -2.7 m or at <em>x</em> = 0.27 m

3 0
3 years ago
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