In the absence of air resistance and friction, what will happen to the velocity of an object going at 20 m/s E?
1 answer:
In the absence of any other forces, the object will continue to move at 20 m/s E.
In fact, Newton's second law states that the resultant of the forces acting on an object is equal to the product between the mass and the acceleration of the object:
therefore, if there are no forces acting on the object, the term on the left is zero, and the acceleration of the object is zero as well. This means that the object will continue its motion with constant speed, and in the same direction.
In fact, Newton's second law states that the resultant of the forces acting on an object is equal to the product between the mass and the acceleration of the object:
therefore, if there are no forces acting on the object, the term on the left is zero, and the acceleration of the object is zero as well. This means that the object will continue its motion with constant speed, and in the same direction.
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The angular speed of the device is 1.03 rad/s.
<h3>What is the conservation of angular momentum?</h3>A spinning system's ability to conserve angular momentum ensures that its spin will not change until it is subjected to an external torque; to put it another way, the rotation's speed will not change as long as the net torque is zero.
Using the conservation of angular momentum
Here, = the system's angular momentum before the collision
= 0 + mv
= (0.005)(450)(0.752)
= 1.692 kgm²/s
The moment of inertia of the system is given by
I = 2(M₁R₁² + M₂R₂²)+ mR₁²
= 2[(1.2)(0.8)² +(0.5)(0.3)²]+0.005(0.8)²
= 1.6292 kgm²
Here, = Iω
So,
1.692 = 1.6292(ω)
ω = 1.03 rad/s
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