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11111nata11111 [884]
4 years ago
7

What is the purpose of the catalyst?

Chemistry
1 answer:
Rama09 [41]4 years ago
3 0
A catalyst either increases (positive catalyst) or decreases (negative catalyst) the rate of the reaction.
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What is the total concentration of phosphate ions (in M) in a 2.1 M aqueous solution of magnesium phosphate?
azamat

Answer:

https://www.usna.edu/Users/chemistry/morse/_files/documents/SC112-Chapter12/keyws12.2.doc

Explanation:

https://www.usna.edu/Users/chemistry/morse/_files/documents/SC112-Chapter12/keyws12.2.doc

work

7 0
3 years ago
List five compound in chemistry and their formula​
enyata [817]

Answer:

Acetic acid CH3COOH

Hydrochloric acid HCl

Sulfuric acid H2SO4

Acetate CH3COO–

Ammonia

Explanation:

Hope i am right

8 0
3 years ago
Density is the ratio of a sample's mass to its volume. A bar of lead has a mass of 115.2 g. When it is submerged in 25.0 mL of w
Margarita [4]

Answer:

$10.97 \ g/cm^3$

Explanation:

Given :

Mass of a bar of lead = 115.2 g

Initial water level $\text{in the graduated cylinder}$ = 25 mL

Final water level $\text{in the graduated cylinder}$ = 35.5 mL

Difference in the water level = 35.5 - 25

                                               = 10.5 mL

                                               = 10.5 \ cm^3

We know that when a body is submerged in water, it displaces its own volume of water.

Therefore, the volume of the lead bar = volume of the water displaced = 10.5 mL  = 10.5 \ cm^3

We know that mathematically, density is the ratio of mass of body to its volume.

Density of the lead bar is given by :

$\rho =\frac{\text{mass}}{\text{volume}}$

$\rho =\frac{\text{115.2 g}}{\text{10.5 cm}^3}$

  = $10.97 \ g/cm^3$

3 0
3 years ago
How do I solve the following word problem: The half-life of Phosphorus - 32 is 14.3 days. It is used to study a plant's use of f
BaLLatris [955]

Half life is the time that it takes for half of the original value of some amount of a radioactive element to decay.

We have the following equation representing the half-life decay:

A=A_o\times2^{(-\frac{t}{t_{half}})_{}_{}}

A is the resulting amount after t time

Ao is the initial amount = 50 mg

t= Elapsed time

t half is the half-life of the substance = 14.3 days

We replace the know values into the equation to have an exponential decay function for a 50mg sample

A=\text{ 50 }\times2^{\frac{-t}{14.3}}

That would be the answer for a)

To know the P-32 remaining after 84 days we have to replace this value in the equation:

\begin{gathered} A=\text{ 50 }\times2^{\frac{-84}{14.3}} \\ A=0.85\text{ mg} \end{gathered}

So, after 84 days the P-32 remaining will be 0.85 mg

4 0
1 year ago
Factors that affect climate:
Tpy6a [65]
Answer: temperature and precipitation are the 2 most important factors that affect climate
7 0
3 years ago
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