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Jlenok [28]
3 years ago
14

Carla is using a fertilizer that contains nitric acid. How is nitric acid classified?

Chemistry
1 answer:
suter [353]3 years ago
4 0

Answer:

Strong acid.....(A)

Explanation:

hope this helps, the person above me is also correct

You might be interested in
Identity the step that is not part of the scientific method.
horrorfan [7]

Options:

conduct an experiment

form a hypothesis

draw a conclusion

state the cause

Answer:

'<u>State the cause'</u> is not part of the scientific method.

Explanation:

The scientific method has three wholistic steps:

  • Test the hypothesis
  • Make observations from the experiment to the hypothesis
  • Draw a conclusion or prediction from the experimental results.

A cause is neither a scientific term nor is it part of the  processes of experimentation.

I hope this was helpful.

6 0
3 years ago
Which of the following pairs of elements is most likely to form an ionic compound? (Hint - question 4 tells you what types of el
mamaluj [8]

\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Ionic bonds.

Since Sodium (Na) is a cation and Chlorine (Cl) is a Anion, they both form a Ionic bond called as NaCl (common salt)

So answer is, Na and Cl

3 0
3 years ago
Explain the role of carbon in mole calculation and definition
vichka [17]

Explanation:

I don't know.

the rock vs the world

4 0
3 years ago
What's the scientific notation for 0.4600
Veseljchak [2.6K]
4.6 x 10 to the -1 power.
5 0
3 years ago
Read 2 more answers
The value of ΔG° at 181.0 °C for the formation of calcium chloride from calcium metal and chlorine gas is ________ kJ/mol. At 25
aleksandr82 [10.1K]

Answer:

\Delta G^{0} at 181.0 ^{0}\textrm{C} is -723.3 kJ/mol.

Explanation:

We know, \Delta G^{0}=\Delta H^{0}-T\Delta S^{0}

where, T is temperature in kelvin.

Let's assume \Delta H^{0} and \Delta S^{0} does not change in the temperature range 25.0 ^{0}\textrm{C}  - 181.0 ^{0}\textrm{C}.

181.0^{0}\textrm{C} = (273+181.0) K = 454.0 K

Hence, at 181.0 ^{0}\textrm{C}, \Delta G^{0}=(-795.8kJ/mol)-[(454.0 K)\times (-159.8\times 10^{-3}kJ/K.mol)]

        = -723.3 kJ/mol

5 0
4 years ago
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