The standard addition equation is as followsI_(S+X) (V/V_O )=I_X+I_X/[X]_i [S]_4 (V_S/V_0 ) Here, [X]_i is the initial concentration of analyte, [S]_i is the initial concentration of standard, I_X is signal for analyte, I_(S+X) is signal for standard and analyte, V_0 is the initial volume, V_S is the added standard volume, and V is the total volume.Added volume of standard V_S is-23.3 mL. Initial volume of the sample V_0 is 10.00 mL. Initial concentration of standard ([S]_i) is 0.156 ng/mL.[X]_i= -[S]_i (V_S/V_0 )〖[X]〗_(i )= -(0.156 ng/mL)((-23.3 mL)/(10.00 mL))=0.363 ng/mL
Concentration of U(III) in ground sample is 0.363 ng/mL
In order to <span>complete and balance the following reactions, you should add a Fe into it. So it will look like uo2+ +cr o^2- 7 ـــــــــــــــــــــ uo2+ +cr3+Fe. The answer to the following given statement or missing answer is Fe. </span>
Answer is: mass of a single silver atom is 1.79·10⁻²² grams.
m(Ag) = 107.87 amu.
The unified atomic mass unit (amu) is a standard unit of atom mass.
One unified atomic mass unit is approximately the mass of one nucleon (1.66·10⁻²⁷ kg).
m(Ag) = 107.87 · 1.66·10⁻²⁷ kg.
m(Ag) = 1.79·10⁻²⁵ kg · 1000 g/kg.
m(Ag) = 1.79·10⁻²² g.
Answer:
No, the experimental result is different from the theoretical value.
Explanation:
Based on the given information, the mass of beaker and watchglass plus alum hydrate is 102.218 grams, and the mass of beaker and watchglass is 101.286 grams. Therefore, the mass of alum hydrate is:
= 102.218 grams - 101.286 grams
= 0.932 grams
Now the mass of anhydrous compound is,
= 102.218 grams - 101.798 grams
= 0.42 grams
Thus, the mass of water present is,
= 0.932 grams - 0.42 grams
= 0.512 grams
The mass percent of water is,
= mass of water/Total mass of hydrate * 100
= 0.512 grams / 0.932 grams * 100
= 54.93 %
Hence, the experimental result in not similar to the theoretical result.
