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Rina8888 [55]
3 years ago
15

Other questions:

Chemistry
1 answer:
vlabodo [156]3 years ago
8 0

Answer:

The functional group present in Cinnamon are : Aromatic , alkene , aldehyde

The functional group present in Almonds : Aromatic , aldehyde

The functional group present in DHA  : Ketone , alcohol

Explanation:

<u>Almond :</u>

Chemical formula : C_{7}H_{6}O

It contain : A benzene ring (Aromatic) , a -CHO group (aldehyde)

<u>Cinnamon Sticks</u> :

Chemical Formula : C_{9}H_{8}O

It contain : A benzene ring (Aromatic) ,an alkene group (C=C) , a -CHO group (aldehyde)

<u> </u><u>DHA:</u>

Chemical Formula : C_{3}H_{6}O_{3}

It contain : Alcohol group (-OH) , ketone group (C=O)

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3 years ago
A 37.2 g sample of copper at 99.8 °C is carefully placed into an insulated container containing 188 g of water at 18.5 °C. Calcu
klasskru [66]

Answer:

T₂ = 19.95°C

Explanation:

From the law of conservation of energy:

Heat\ Lost\ by\ Copper = Heat\ Gained\ by\ Water\\m_cC_c\Delta T_c = m_wC_w\Delta T_w

where,

mc = mass of copper = 37.2 g

Cc = specific heat of copper = 0.385 J/g.°C

mw = mass of water = 188 g

Cw = specific heat of water = 4.184 J/g.°C

ΔTc = Change in temperature of copper = 99.8°C - T₂

ΔTw = Change in temperature of water = T₂ - 18.5°C

T₂ = Final Temperature at Equilibrium = ?

Therefore,

(37.2\ g)(0.385\ J/g.^oC)(99.8\ ^oC-T_2)=(188\ g)(4.184\ J/g.^oC)(T_2-18.5\ ^oC)\\99.8\ ^oC-T_2 = \frac{(188\ g)(4.184\ J/g.^oC)}{(37.2\ g)(0.385\ J/g.^oC)}(T_2-18.5\ ^oC)\\\\99.8\ ^oC-T_2 = (54.92) (T_2-18.5\ ^oC)\\54.92T_2+T_2 = 99.8\ ^oC + 1016.02\ ^oC\\\\T_2 = \frac{1115.82\ ^oC}{55.92}

<u>T₂ = 19.95°C</u>

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Which is true of a molecule?
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All molecules of a compound have the same properties. The chemical properties of any individual compound would not change. The molecule is one of the smallest particles in any element that has the chemical properties of that element. Molecules are made of atoms.

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The answer would be D because from my research it's the only one that didn't have a catalyst 
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