Question

In the following combustion reaction of acetylene (C2H2), how many liters of CO2 will be produced if 60 liters of O2 is used, given that both gases are at STP?
2C2H2+5O2 2H2O+4CO2

The volume of one mole of gas at STP is 22.4 liters.

Answer 1

The stoichiometry of the reaction is 5 mols of O2 produces 4 mols of CO2.

1 mol at STP is equivalent to 22.4 liters.

So, 5*22.4 liters of O2 produces 4*22.44 liters of CO2

Then 60 liters of O2 produces 60*4/5 = 48 liters of CO2