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3 years ago

Write a full chemical equation for the reactions between magnesium and sulfuric acid

Chemistry

1 answer:

melamori03 [73]3 years ago

6 0

Answer:

magnesium + hydrochloric acid → hydrogen gas + magnesium chloride

explanation:

the nitrogen in HNO3 is in the +5 oxidation state and is easily reduced. The reduction would result in the oxidation of the hydrogen gas, forming the water once again.The sulfur in H2SO4 is also in its highest oxidation state, +6.

Hope this helps :)

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Describe how to find the area of a triangle (do not just give the formula)

NemiM [27]

When you have the bottom measurement of the triangle (base) and the height of the triangle in the center, you multiply them together and then divide by 2.

~Do you need more explaining~?

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3 years ago

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Anastaziya [24]

Answer:

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Explanation:

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2 years ago

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gizmo_the_mogwai [7]

Answer:

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3 years ago

Read 2 more answers

Glucose, C 6 H 12 O 6 , is used as an energy source by the human body. The overall reaction in the body is described by the equa

MA_775_DIABLO [31]

Answer:

$m_{O_2}=61.87gO_2$

$m_{CO_2}=85.07gCO_2$

Explanation:

Hello,

Considering the given reaction's stoichiometry, grams of oxygen result:

$m_{O_2}=58.0gC_6H_{12}O_6*\frac{1molC_6H_{12}O_6}{180gC_6H_{12}O_6}*\frac{6molO_2}{1molC_6H_{12}O_6}*\frac{32gO_2}{1molO_2}\\m_{O_2}=61.87gO_2$

Moreover, the mass of produced carbon dioxide turns out:

$m_{CO_2}=58.0gC_6H_{12}O_6*\frac{1molC_6H_{12}O_6}{180gC_6H_{12}O_6}*\frac{6molCO_2}{1molC_6H_{12}O_6}*\frac{44gCO_2}{1molCO_2}\\m_{O_2}=85.07gCO_2$

Best regards.

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3 years ago

What is the wavelength of light emitted when the electron in a hydrogen atom undergoes transition from an energy level with n =

Lady bird [3.3K]

Answer:

$4.86\times10^{-7}\ \text{m}$

Explanation:

R = Rydberg constant = $1.09677583\times 10^7\ \text{m}^{-1}$

$n_1$ = Principal quantum number of an energy level = 2

$n_2$ = Principal quantum number of an energy level for the atomic electron transition = 4

Wavelength is given by the Rydberg formula

$\lambda^{-1}=R\left(\dfrac{1}{n_1^2}-\dfrac{1}{n_2^2}\right)\\\Rightarrow \lambda^{-1}=1.09677583\times 10^7\left(\dfrac{1}{2^2}-\dfrac{1}{4^2}\right)\\\Rightarrow \lambda=\left(1.09677583\times 10^7\left(\dfrac{1}{2^2}-\dfrac{1}{4^2}\right)\right)^{-1}\\\Rightarrow \lambda=4.86\times10^{-7}\ \text{m}$

The wavelength of the light emitted is $4.86\times10^{-7}\ \text{m}$ .

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3 years ago