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gladu [14]
3 years ago
15

It was a children versus grown-ups competition at school. One event required the adult to throw a basketball as far as he could.

When it was the child's turn, he had to throw a baseball instead. The event coordinator said, "It's only fair!" Based on Newton's laws, was this event fair?
(A)Yes, because an adult can apply more force than a child can. Making the adult's object bigger than the child's object helps to even out the acceleration.
(B)No, because a basketball is bigger than a baseball, and objects that are bigger accelerate slower.
(C)Yes, because acceleration doesn't depend on the size of the object.
(D)No, because you must have the same size object in a competition.
Physics
2 answers:
Rudik [331]3 years ago
7 0

the answer is: (D) No, because you must have the same size object in a competition.

Cerrena [4.2K]3 years ago
3 0
D Because If Your Going To Have A Contest Its Ganna Have To Be The Same Objectives For Both Contenders 
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kompoz [17]

Answer:

0.5 m/s².

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Final velocity (v) = 10 m/s

Time (t) = 20 s

Acceleration (a) =?

Acceleration can simply be defined as the rate of change of velocity with time. Mathematically, it is expressed as:

a = (v – u) / t

Where:

a is the acceleration.

v is the final velocity.

u is the initial velocity.

t is the time.

With the above formula, we can obtain the acceleration of the car as follow:

Initial velocity (u) = 0 m/s

Final velocity (v) = 10 m/s

Time (t) = 20 s

Acceleration (a) =?

a = (v – u) / t

a = (10 – 0) / 20

a = 10/20

a = 0.5 m/s²

Therefore, the acceleration of the car is 0.5 m/s².

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2 years ago
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shtirl [24]
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5 0
3 years ago
How much tension must a rope withstand if it is used to accelerate a 6526 kg car vertically upwards at 8.9 m/s^2?
ExtremeBDS [4]

Answer:

The value is T =  122036.2 \  N

Explanation:

From the question we are told that

     The mass of the car is  m  = 6526 \  kg

      The acceleration  is  a=  8.9 \  m/s^2

Generally the net force applied on the rope is mathematically represented as

          F_{net}   =  T -  W

Here W is the weight of the car which is evaluated as

         W =  m * g

=>      W =  6526  * 9.8

=>       W =  63954.8 \  N

Generally the net force can also be mathematically represented as

       F =  m * a

So

        m * a  =  T  -  63954.8

=>     6526  *  8.9 =  T  -  63954.8

=>      T =  122036.2 \  N

7 0
2 years ago
Suppose the wavelength of the light is 550 nm . How much farther is it from the dot on the screen in the center of fringe E to t
Bogdan [553]

Complete question:

Suppose the wavelength of the light is 550 nm . How much farther is it from the dot on the screen in the center of fringe E to the left slit than it is from the dot to the right slit? Fringe C is the central maximum.

Check the image uploaded.

Answer:

The difference is 1100 nm

Explanation:

A bright fringe creates constructive interference, the wavelength is always in a multiple form.

At center fringe, the difference is (550 nm)(0) = 0

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For the second maximum, the difference = (550 nm)(2) = 1100 nm

Thus, for nth maxima, the difference is (550 nm)(n)

From the image uploaded, C is located on the second maximum, therefore the difference is given as  (550 nm)(2) = 1100 nm

Therefore, the dot on the screen in the center of fringe E to the left slit is 1100 nm

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