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matrenka [14]
1 year ago
7

Two (2) moles of an ideal gas are in a container at 200 kpa and a temperature of 300 k. The volume occupied by the gas in the co

ntainer is?
Chemistry
1 answer:
k0ka [10]1 year ago
4 0

The volume occupied by the gas in the container is 1 m³

Boyles law applies

P₁ V₁ = P₂ V₂

Where P₁ = 200kpa

P₂ = 300kpa

if its initial volume is 1.5

then,

P₁ V₁ = P₂ V₂

200 × 1.5 = 300 × V₂

V₂ = 200 × 1.5 / 300

    = 1 m³

Hence  the volume occupied by the gas container is 1 m³

Learn more about the Boyles law on

brainly.com/question/13759555

#SPJ4

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So, the final answer be come<em> </em>

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9. How many grams of potassium sulfate are needed to make 250 mL of a 0.150 M
antiseptic1488 [7]

Answer:

6.53g of K₂SO₄

Explanation:

Formula of the compound is K₂SO₄

Given parameters:

Volume of K₂SO₄ = 250mL = 250 x 10⁻³L

= 0.25L

Concentration of K₂SO₄ = 0.15M or 0. 15mol/L

Unknown:

Mass of K₂SO₄ =?

Methods:

We use the mole concept to solve this kind of problem.

>>First, we find the number of moles using the expression below:

Number of moles= concentration x volume

Solving for number of moles:

Number of moles = 0.25 x 01.5

= 0.0375mole

>>Secondly, we use the number of moles to find the mass of K₂SO₄ needed. This can be obtained using the expression below:

Mass(g) = number of moles x molar mass

Solving:

To find the molar mass of K₂SO₄, we must know the atomic mass of each element in the compound. This can be obtained using the periodic table.

For:

K = 39g

S = 32g

O = 16g

Molar mass of K₂SO₄ = (39x2) + 32 + (16x4)

= 78 +32 + 64

= 174g/mol

Using the expression:

Mass(g) = number of moles x molar mass

Mass of K₂SO₄ = 0.0375 x 174 = 6.53g

5 0
3 years ago
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