Answer:
Option D is correct = 8.12 grams of NaCl
Explanation:
Given data:
Moles of sodium chloride = 0.14 mol
Mass of sodium chloride = ?
Solution:
Formula:
Number of moles = mass of NaCl / Molar mass of NaCl
Molar mass of NaCl = 58 g/mol
Now we will put the values in formula.
0.14 mol = Mass of NaCl / 58 g/mol
Mass of NaCl = 0.14 mol × 58 g/mol
Mass of NaCl = 8.12 g of NaCl
Thus, 0.14 moles of NaCl contain 8.12 g of NaCl.
Answer:
False
Explanation:
We can see the colors of the rainbow, therefore they are visible.
The psychical properties do no change the composition of the lithium metal.
The chemical properties will change the composition of the lithium producing other substances.
light enough to float on water - physical property
silvery gray in color - physical property
changes from silvery gray to black when placed in moist air - chemical property
(in air the lithium will react with the oxygen forming the oxide which have a black color)
can be cut with a sharp knife - physical property
in the liquid state, it boils at 1317 °C - physical property
reacts violently with chlorine to form a white solid - chemical property
in the liquid state, it reacts spontaneously with its glass container, producing a hole in the container - chemical property
burns in oxygen with a bright red flame - chemical property
Answer:
A)
Explanation:
Heat moves from where it's hot, to where it's not
Answer: The molecular formula of the compound is 
Explanation:
Converting all these percentages into mass.
We take the total mass of the compound to be 100 grams, so, the percentages given for each element becomes its mass.So, the mass of each element is equal to the percentage given.
Mass of N = 30.45 g
Mass of O = 69.55 g
Step 1 : convert given masses into moles.
Moles of N=
Moles of O = 
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For N = 
For O =
The ratio of N: O = 1: 2
Hence the empirical formula is
.
Empirical mass of
is = 14(1)+16 (2)=46
The equation used to calculate the valency is:

Step 3: To calculate the molecular formula=
Hence, the molecular formula of the compound is 