Abbreviation for mole

How many protons and electrons are in a

Pie

Answer:

B 29 protons, 27 electrons

Explanation:

The given specie is copper ion:

Cu²⁺

We are to find the number of protons and electrons it contains.

The number of protons is the positively charged particles in the atom.

Electrons are the negatively charged particles in the atom.

The number of protons is the same as the atomic number

Atomic number of copper = 29

Number of protons = 29

Now;

Charge = Number of protons - Number of electrons

2 = 29 - number of electrons

-27 = - number of electrons

Number of electrons = 27

3 0

3 years ago

PLEASE HELP!!

omeli [17]

Answer:

8/3 hours

Explanation:

12.5/100=1/8, 1/8*2=2/8=1/4 1/4*2=1/2 1/2*2 = 1 (whole)

we multiplyed 1/8 by two three times to get 1 so 8/3 hours is the answer

by the way i'm in 6th grade

3 0

3 years ago

Read 2 more answers

Complete the passage about metallic bonding.

Burka [1]

Answer:

some bonds are broken and new ones are formed. Now you are ready to learn more about those bonds. Chemical bonds are attractions between atoms. They are simply attractive forces (between the + nucleus of one atom and the - electrons of a neighboring atom) that hold groups of atoms together and make them function as a unit.

7 0

3 years ago

3. 2 HCl (aq)

tekilochka [14]

Explanation:

balance the equation ...HCl,Ba(OH) and BaCl2 are aqueous

know groups of the elements H 1+ ,Cl -,Ba 2+,OH-

write complete ionic eqution and eliminate spectator ions those appearing on both sides Cl and Ba

6 0

3 years ago

A sample of P2Cl5 contains 179 g of phosphorous, how many grams of chlorine are present? Please show step by step thx!

natima [27]

Answer:

About 512 g.

Explanation:

We are given a sample of P₂Cl₅ that contains 179 grams of phosphorus, and we want to determine the grams of chlroine that is present.

Thus, we can convert from grams of phosphorus to moles of phosphorus, moles of phosphorus to moles of chlorine, and moles of chlorine to grams of chlorine.

From the formula, there are two moles of P for every five moles of Cl. The molecular weights of P and Cl are 30.97 g/mol and 35.45 g/mol, respectively. Hence:

$\displaystyle 179\text{ g P} \cdot \frac{1\text{ mol P}}{30.97\text{ g P}} \cdot \frac{5\text{ mol Cl}}{2\text{ mol P}} \cdot \frac{35.45\text{ g Cl}}{1\text{ mol Cl}} = 512\text{ g Cl}$

In conclusion, there is about 512 grams of chlorine present in the sample.

Alternatively, we can mass percentages. The mass percent of phosphorus in P₂Cl₅ is:

$\displaystyle \% \text{P} = \frac{2(30.97)}{5(35.45) + 2(30.97)} = 25.90\%$

Because there are 179 grams of phosphorus, the total amount of sample present is:

$\displaystyle \begin{aligned} 25.90\% \cdot m_T & = 179\text{ g P} \\ \\ m_T & = 691.1 \text{ g}\end{aligned}$

Therefore, the amount of chlorine present is 691.1 g - 179 g, or about 512 g, in agreement with our above answer.

8 0

3 years ago