Ask question

Ask question

All categories

katrin2010 [14]

3 years ago

12

How many sig figs are in 10

1 answer:

Eddi Din [679]3 years ago

3 0

Answer:

One (1) significant figure.

Step-by-step explanation:

All non zero digits are always significant zeros. Since there is no decimal point, the 0 is a trailing zero, and does not count as a significant figure.

You might be interested in

Kryger [21]

Answer:

D. Yes, since the slopes are the same and the y-intercepts are different.

Step-by-step explanation:

yes because both line have a slope of .857/2

...................................................................................................................................................

yes; both have a slope of 3/7

...................................................................................................................................................

Yes. They have the same slope.

8 0

2 years ago

Is 168/54 in simplest form?

Brut [27]

No, because both can be divided by two. in simplist form it is 3 1/9

6 0

3 years ago

Ellie and Jamie like to bake cookies. Ellie baked 24 chocolate chip cookies, and Jamie baked p peanut butter cookies. Together t

kirza4 [7]

Answer:

C) p + 24 = 56

Step-by-step explanation:

The total number of cookies baked = Number of cookies Ellie baked + Number of cookies Jamie baked

Ellie baked 24 chocolate chip cookies.

Jamie baked p peanut butter cookies.

Total of 56 cookies.

Hence:

56 = p + 24

Therefore, the equation that can be solved for p to find the number of cookies Jamie baked is

p + 24 = 56

Option C is the correct option

7 0

3 years ago

Jeff has a density of 1000 g/mL and a volume of 25-mL. What is Jeff’s mass?

zlopas [31]

Answer:

25,000 grams

Step-by-step explanation:

Density can be found using the following formula:

$d=\frac{m}{v}$

If we rearrange the formula for $m$ , mass, we will multiply both sides of the equation by v.

$d*v=\frac{m}{v}*v$

$d*v=m$

The mass can be found by multiplying the density by the volume.

Jeff's density is 1000 grams per milliliter and his volume is 25 milliliters.

$d= 1000 g/mL\\v=25 mL$

Substitute the values into the formula.

$m=d*v$

$m= 1000 g/mL * 25 mL$

Multiply. When you multiply, the "mL" or milliliters will cancel out.

$m= 1000 g * 25$

$m= 25000 g$

Jeff's mass is 25,000 grams.

6 0

3 years ago

Answers fast please. 1.) y=x−63x+2y=8 Use the substitution method. A.) (4, −2) B.) (14, 8) C.) (0, −6) D.) (3, −3) 2.) What is t

GrogVix [38]

<u>QUESTION 1</u>

The given system of equation is

$y=x-6...eqn1$

and

$3x+2y=8...eqn2$

Let us substitute equation (1) into equation (2) to get,

$3x+2(x-6)=8$

We expand the bracket to get,

$3x+2x-12=8$

We simplify to get.

$5x-12=8$

We group like terms to get

$5x=8+12$

$\Rightarrow 5x=20$

$\Rightarrow x=4$

We now substitute $x=4$ in to equation (1) to obtain,

$y=4-6=-2$

The correct answer is option A.

<u>QUESTION 2</u>

The given system of equations is

$y-x=9...eqn1$

and

$10+2x=-2y...eqn2$

We make y the subject in equation (2) to get,

$y=-x-5..eqn3$

We put equation (3) into equation (1) to obtain,

$-x-5-x=9$

We group like terms to get,

$-x-x=9+5$

This implies that,

$-2x=14$

We divide through by $-2$ to get,

$x=-7$

Hence the x-coordinate is $-7$

<u>QUESTION 3</u>

The given system is

$y=3x-1..eqn1$

and

$x-y=-9...eqn2$

We make $x$ the subject in equation (2) to get,

$x=y-9...eqn3$

We put equation (3) into equation (1) to obtain,

$y=3(y-9)-1$

We expand the bracket to get,

$y=3y-27-1$

Group like terms to get,

$y-3y=-27-1$

We simplify to get;

$-2y=-28$

This implies that,

$y=14$

Therefore the y-coordinate is 14.

4 0

4 years ago

Read 2 more answers