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blsea [12.9K]
4 years ago
6

Sunlight shining through a clear window it’s Jeremy’s face while he does his homework he uses a large wooden wooden block to cov

er the window what do the wooden block in the clear window demonstrate
Chemistry
2 answers:
lidiya [134]4 years ago
4 0

Answer:

a blocker?

Explanation:

just a guess

Deffense [45]4 years ago
3 0
I would have to know the subject
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Acid deposition would most likely result in_________
luda_lava [24]

Answer: Acid rain.

Explanation:

According to some experts, acid precipitation can lead to acid rain. Acid rain is a product of chemical reactions caused by the release of compounds such as sulfur dioxide and nitrogen oxides into the air. These substances can form in the atmosphere itself and react with water, oxygen, and other chemicals to form more acidic pollutants, known as acid rain.

There are specific theories that nitrogen oxides cause acid rain, in other sulfur oxides, which are produced by the combustion of coal or petroleum products, for example, in thermal power plants, automobile engines, and plants for the production and purification of metals. With water vapor, they produce nitric or sulfuric acid, respectively. This natural disaster is very bad for flora and fauna, it has a particular negative reflection on forests and the aquatic world, especially fish.

7 0
3 years ago
How many moles of gold, Au, are in 3.60 x 10^-5 g of gold?
zlopas [31]
<h3>Answer:</h3>

1.83 × 10⁻⁷ mol Au

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.60 × 10⁻⁵ g Au (Gold)

<u>Step 2: Identify Conversions</u>

Molar Mass of Au - 196.97 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 3.60 \cdot 10^{-5} \ g \ Au(\frac{1 \ mol \ Au}{196.97 \ g \ Au})
  2. Multiply:                            \displaystyle 1.82769 \cdot 10^{-7} \ mol \ Au

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.82769 × 10⁻⁷ mol Au ≈ 1.83 × 10⁻⁷ mol Au

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