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3 years ago

6

Sunlight shining through a clear window it’s Jeremy’s face while he does his homework he uses a large wooden wooden block to cov

er the window what do the wooden block in the clear window demonstrate

2 answers:

lidiya [134]3 years ago

4 0

Answer:

a blocker?

Explanation:

just a guess

Deffense [45]3 years ago

3 0

I would have to know the subject

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the equation demonstrates a reaction of sodium chloride and fluorine. 2NaCl+F2=2NaF+Cl2. in order for the reaction to proceed, f

slamgirl [31]

Answer: You would need 1 mole of Fluorine

Explanation:The equation is already balanced so just looking at the coefficients in the equation we can see that Sodium Chloride (2NaCl) needs two moles for this equation and fluorine (F2) only needs one.

6 0

3 years ago

Pure R,R-hydrobenzoin (side product of meso-hydrobenzoin) has a melting point of 148°C. a) What do you expect the melting point

Alexandra [31]

Answer:

Explanation:

(a) melting point of S,S-hydrobenzoin should be 140°C. Since S,S-hydrobezoin and R,R-hydrobenzoin are enantiomeric pair so that their melting point and boilong point should be same.

(b) different melting point,

Racemic mixture must have different melting point in comparison to the pure enantiomers.

considering a racemic mixture, individual enantiometer possesses a greater affinity for its kind of molecules than for those of the other enantiometer

3 0

3 years ago

Why is it that the north star is the only star in the night sky that seems to stay still

Masja [62]

I think it is because it is directly about the north or south pole (I forget) so while all the other stars seem to rotate around because the Earth is rotating but the North Star is directly in the center. Don't take my word though.

8 0

4 years ago

38 mL of a gas was collected at 581 mm Hg and 25 degrees Celsius. What would the volume be at standard pressure (560 mm Hg) if t

Talja [164]

Idk man sorry nfnnekernsekekee

7 0

3 years ago

Write equations that show the processes that describe the first, second, and third ionization energies for a gaseous gadolinium

Inessa [10]

Answer:

Gd(g) → $Gd^{+}(g) + e^{-}$ , $Gd^{+}(g)$ → $Gd^{2+}(g) + e^{-}$ , $Gd^{2+}(g)$ → $Gd^{3+}(g) + e^{-}$

Explanation:

Ionization energy is the energy required to remove an electron from a gaseous atom or ion.

The first ionization energy is the energy required to remove the valence electron(outermost) from a neutral atom:

Gd(g)→ $Gd^{+}(g) + e^{-}$

The second ionization energy is the energy required to remove next/second electron from $x^{+}$ ion. The second ionization energy is always higher than the first:

$Gd^{+}$ (g) → $Gd^{2+}(g) + e^{-}$

The third ionization energy is the energy required to remove third electron from $x^{2+}$ ion:

$Gd^{2+}$ (g) → $Gd^{3+}(g) + e^{-}$

5 0

3 years ago