A 10-kg mass slides down a flat hill that makes an angle of 10° with the horizontal. If friction is negligible, what is the resu
1 answer:
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Answer:
The magnitude of the hiker’s displacement is 2.96 km
Explanation:
Let the initial displacement of the hiker, = x = 2km
the final displacement of the hiker, = y = 1.4 km
The resultant of the two vectors, According to Pythagorean theorem is the vector sum of the two vectors.
R' = x' + y'
Check the image uploaded for solution;
Answer:
Explanation:
Given that
Length = L
At initial over hanging length = Xo
Lets take the length =X after time t
The velocity of length will become V
Now by energy conservation
So
We know that
At t= 0 ,X=Xo
So we can say that
So the length of cable after time t
Answer
given,
mass of the = m₁ = 8.75 Kg
another mass of the object = m₂ = 14 Kg
distance between them = 50 cm
R₁ = 17 cm
R₂ = 50 -17 = 33 cm
a) Force applied due to the Mass 8.75 in +ve x- direction
Force applied due to mass 14 Kg in -ve x-direction
net force
F = F₁ + F₂
Using newton second law
b) As the acceleration of mass comes out to be +ve hence, the direction will be toward the mass of 8.75 Kg