Answer:
V = 26.95 cm³
Explanation:
Density is given by the formula :
ρ = m÷V
Density = mass ÷ Volume
Given both density and mass we rearrange, substitute and solve for Volume :
Rearranging the equation to make Volume the subject :
ρ = m÷V
ρV = m
V = m÷ ρ
Now substitute :
V = 45 ÷ 1.67
V = 26.9461077844
Take 2 decimal places as the density is 2 decimal places :
V = 26.95
Units will be cm³ as it is volume
Hope this helped and have a good day
Answer:
real, inverted, and smaller than the object
Explanation:
When the object is placed beyond the center of curvature, the image will formed between the focus and the center of curvature. The size of the image is diminished and its nature is real and inverted.
The whole description is shown in the attached figure. It is clear that the size of the image is smaller than the object.
Work done = force * distance
work done = 200 * 20
work done = 4000J
Answer:
a) 
b) 
c) 
d) 
Explanation:
<u>Given equation of pressure variation:</u>
![\Delta P= (1.78\ Pa)\ sin\ [(0.888\ m^{-1})x-(500\ s^{-1})t]](https://tex.z-dn.net/?f=%5CDelta%20P%3D%20%281.78%5C%20Pa%29%5C%20sin%5C%20%5B%280.888%5C%20m%5E%7B-1%7D%29x-%28500%5C%20s%5E%7B-1%7D%29t%5D)
We have the standard equation of periodic oscillations:

<em>By comparing, we deduce:</em>
(a)
amplitude:

(b)
angular frequency:


∴Frequency of oscillations:


(c)
wavelength is given by:



(d)
Speed of the wave is gives by:



Answer:
The density of gold is of 18 grams per cm3.
Explanation:
The mass density of a homogeneous material expresses how much mass of that material is present in a given volume. Since the density of an object is obtained by dividing its mass by its volume, to obtain the density of gold, its 90 grams of mass must be divided by its 5 cm3 volume, performing the following calculation:
90/5 = X
18 = X
Thus, the density of gold is 18 grams per cm3.