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Neporo4naja [7]
3 years ago
6

Professor Whitney has a sample of lead and a sample of iron. The samples have equal mass. When Whitney heats the samples, the le

ad reaches a higher temperature than the iron, even though both samples absorbed the same amount of thermal energy. What can Whitney conclude from this experiment?
Physics
1 answer:
xenn [34]3 years ago
8 0
The temperature increase of a substance is T=Q/m*c, where m is the mass, Q is the energy absorbed and c is the specific heat.  So you can conclude that if the lead gets to a higher temperature, it must have a lower specific heat
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A square plate of side 9 m is submerged in water at an incline of 60∘ with the horizontal. Its top edge is located at the surfac
Tpy6a [65]

Answer:

The force on one side of  the plate is 3093529.3 N.

Explanation:

Given that,

Side of square plate = 9 m

Angle = 60°

Water weight density = 9800 N/m³

Length of small strip is

y=\dfrac{\Delta y}{\sin60}

y=\dfrac{2\Delta y}{\sqrt{3}}

The area of strip is

dA=\dfrac{9\times2\Delta y}{\sqrt{3}}

We need to calculate the force on  one side of  the plate

Using formula of pressure

P=\dfrac{dF}{dA}

dF=P\times dA

On integrating

\int{dF}=\int_{0}^{9\sin60}{\rho g\times y\times 6\sqrt{3}dy}

F=9800\times6\sqrt{3}(\dfrac{y^2}{2})_{0}^{9\sin60}

F=9800\times6\sqrt{3}\times(\dfrac{(9\sin60)^2}{2})

F=3093529.3\ N

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What property of equality can be used to solve the equation. n – 14 = 25
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28. A stone is projected at a cliff of height h with an initial speed of 42.0 mls directed at angle θ0 = 60.0° above the horizon
Julli [10]

Answer:

a) 51.8 m, b) 27.4 m/s, c) 142 m

Explanation:

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v₀ = 42.0 m/s

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t = 5.50 s

Find:

h, v, and H

a) y = y₀ + v₀ᵧ t + ½ gt²

0 = h + (42.0 sin 60.0) (5.50) + ½ (-9.8) (5.50)²

h = 51.8 m

b) vᵧ = gt + v₀ᵧ

vᵧ = (-9.8)(5.5) + (42.0 sin 60.0)

vᵧ = -17.5 m/s

vₓ = 42.0 cos 60.0

vₓ = 21.0 m/s

v² = vₓ² + vᵧ²

v = 27.4 m/s

c) vᵧ² = v₀ᵧ² + 2g(y - y₀)

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