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3 years ago

The answers!!! Q53 to 56

Physics

1 answer:

nexus9112 [7]3 years ago

3 0

Answer:

See the explanation below.

Explanation:

53) Yes, this process is called latent heat transfer, it happens when heat is transferred to a body or a substance, an increase in its energy is observed without presenting an increase in temperature. An example of this can be seen in the evaporation of water.

54) It absorbs energy since heat transfer always occurs from a space of higher temperature to another with lower temperature so as the wax freezes the heat is transferred from the environment to the wax.

55) The water vapor and wet air will be absorbed by the canvas, the heat contained in this water vapor will be absorbed by the canvas in this way decreases the temperature of the water inside the canteen.

56) The process is vaporization. The refrigerant of the air conditioning equipment enters the coil, in the form of liquid, this liquid is at low temperature, so that the room air at a higher temperature, exchanges heat with the refrigerant liquid, the refrigerant liquid changes the phase of liquid to vapor, for when it is completely vaporized this can be sucked by the compressor equipment.

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Answer:

D (density) = Mass / Volume

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V = 50 kg / .92 kg / L

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V = 54.3 L the mass does not change upon the change of phase (freezing)

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3 years ago

Parallel Plates Consider a very large conducting plate at potential V0 suspended a distance d above a very large grounded plane.

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Answer:

$V = \frac{V_0x}{d}$

Explanation:

Since the field lines are parallel and the electric field is uniform between two parallel plates, a test charge would experience the same force of attraction or repulsion no matter where it is located in the field,

I attached an image that could help to understand the representation of the field. The formula used to calculate it is given by,

$E= -\frac{\Delta V}{x}$ (1)

If we want to consider the change in Voltage with respect to the position then it would be,

$E= -\frac{dV}{dx}$

According to the information provided, the potential is $V_0$ and there is a distance d, therefore

$E= -\frac{V_0}{d}$ (2)

Taking equation (1) we can clear V, to what we have,

$\frac{dV}{dx} = -E$

$dV = -Edx$

Integrating,

$V= - \int Edx$

Substituting (2)

$V = -\int \frac{V_0}{d} dx$

$V = \frac{V_0x}{d}$

Where x is the height from the grounded plate.

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