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3 years ago

Which of the following is an example of potential energy?

Physics

2 answers:

mamaluj [8]3 years ago

8 0

Answer:

B. A rubber band is stretched out

Explanation:

nika2105 [10]3 years ago

7 0

Answer:

<h2>your answer is like this</h2>

Explanation:

<h2>B) Rubber band is stretched out</h2>

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A roller coaster is at the top of a hill and rolls to the top of a lower hill if mechanical energy is constant then on the top o

mafiozo [28]

The kinetic energy is greater on the second hill

hope i helped have a great day

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3 years ago

If all of the forces acting on an object balance so that the net force is zero, then

nadya68 [22]

The answer is (A) the object must be at rest.

When all of the forces acting on an object balance, the net force is zero and hence the object will not move.

Yes, the direction might also change under some special circumstances.

6 0

3 years ago

Multi celled organisms have a ______ surface area to volume ratio than single celled organisms.

True [87]

A. Larger. It is larger Bc they r all larger than the other

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3 years ago

People, especially adults, are inactive because of "passive" modes of transportation.

enot [183]

The drop in physical activity is partly due to inaction during leisure time and sedentary behaviour on the job and at home. Likewise, an increase in the use of "passive" modes of transportation also contributes to insufficient physical activity.

3 0

3 years ago

A police car is traveling north on a straight road at a constant 16.0 m/s. An SUV traveling north at 30.0 m/s passes the police

Nastasia [14]

Answer:

It will take 15.55s for the police car to pass the SUV

Explanation:

We first have to establish that both the police car and the SUV will travel the same distance in the same amount of time. The police car is moving at constant velocity and the SUV is experiencing a deceleration. Thus we will use two distance fromulas (for constant and accelerated motions) with the same variable for t and x:

1. $x=x_{0}+vt$

2. $x=x_{0}+v_{0}t+\frac{at^{2}}{2}$

Since both cars will travel the same distance x, we can equal both formulas and solve for t:

$vt = v_{0}t+\frac{at^2}{2}\\\\ 16\frac{m}{s}t =30\frac{m}{s}t-\frac{1.8\frac{m}{s^{2}} t^{2}}{2}$

We simplify the fraction present and rearrange for our formula so that it equals 0:

$0.9\frac{m}{s^{2}} t^{2}-14\frac{m}{s}t=0 \\\\ t(0.9\frac{m}{s^{2}}t-14\frac{m}{s})=0$

In the very last step we factored a common factor t. There is two possible solutions to the equation at $t=0$ and:

$0.9\frac{m}{s^{2}}t-14\frac{m}{s}=0 \\\\ 0.9\frac{m}{s^{2}}t =14\frac{m}{s} \\\\ t =\frac{14\frac{m}{s}}{0.9\frac{m}{s^{2}}}=15.56s$

What this means is that during the displacement of the police car and SUV, there will be two moments in time where they will be next to each other; at $t=0 s$ (when the SUV passed the police car) and $t=15.56s$ (when the police car catches up to the SUV)

8 0

3 years ago