Answer:
Electric field, E = 0.064 V/m
Explanation:
It is given that,
Resistivity of silver wire, 
Current density of the wire, 
We need to find the magnitude of the electric field inside the wire. The relationship between electric field and the current density is given by :


E = 0.0636 V/m
or
E = 0.064 V/m
So, the magnitude of electric field inside the wire is 0.064 V/m. Hence, this is the required solution.
Answer The fringes become closer together as the slits are moved farther apart.
Answer:
it will be d) 14.4W
Explanation:
potential difference (v) = 12 volts
resistance (r) = 10 ohms
now, we know
=》

=》

=》

=》

Answer:
c is the answer because it i in a series not a parallel circut.
Explanation: