All categories

2 years ago

Much power does a 10 Ohm bulb have in a series circuit with a battery of 12V and nothing else in the the circuit?

Physics

1 answer:

Sedaia [141]2 years ago

8 0

Answer:

it will be d) 14.4W

Explanation:

potential difference (v) = 12 volts

resistance (r) = 10 ohms

now, we know

=》

$power = \frac{v {}^{2} }{r}$

=》

$power \: = \frac{12 {}^{2} }{10}$

=》

$power = \frac{144}{10}$

=》

$power = 14.4 \: watt$

You might be interested in

2 ways to change frictional force between 2 objects

Zanzabum

In order to change the frictional force between two solid surfaces, it can be changed by shorter distances and by the amount of weight it has or the amount of force that is pushing that object to go however distance it can.

5 0

3 years ago

Read 2 more answers

WILL GIVE BRAINLIEST ASAP

Sedaia [141]

Explanation:

1. Height Relatives to reference point, Mass, and strength of the gravitational field it's in

2. Distance in the magnetic field

8 0

2 years ago

Calculate the energy used by a radio of power 30W in 1 minute.

Alekssandra [29.7K]

Answer:

1.8kJ

Explanation:

Formula :

Energy used = Power x time

===============================================================

Given :

⇒ Power = 30 W

⇒ Time = 1 minute = 60 seconds

=============================================================

Solving :

⇒ Energy used = 30 W × 60 s

⇒ Energy used = 1,800 J

⇒ Energy used = 1.8kJ

5 0

2 years ago

Read 2 more answers

Sally and Sam are in a spaceship that comes to within 17,000 km of the asteroid Ceres. Determine the force Sally experiences, in

MAXImum [283]

Answer:

0.01606 Newtons

Explanation:

r = Distance between the asteroid and Sally = 17000000 m

m₁ = Mass of the asteroid = 8.7× 10²⁰ kg

m₂ = Mass of Sally = 80 kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

From Newton's Universal law of gravity

$F=G\frac{m_1m_2}{r^2}\\\Rightarrow F=6.67\times 10^{-11}\times \frac{8.7\times 10^{20}\times 80}{17000000^2}\\\Rightarrow F=0.01606\ N$

The force Sally experiences is 0.01606 Newtons

8 0

3 years ago

Two equally charged, 2.098 g spheres are placed with 3.338 cm between their centers. When released, each begins to accelerate at

photoshop1234 [79]

Answer:

$2.64\times 10^{-7} C$

Explanation:

There are two spheres name 1 and 2 and they posses the same charge, which is +q.

And they have equal mass which is 2.098 g.

The distance between these two spheres is, $r=3.338 cm$ .

And the acceleration of each sphere is, $a=269.429 m/s^{2}$ .

Now the coulumbian force experience by 1 sphere due to 2 sphere,

$F_{21} =\frac{q^{2} }{4\pi\epsilon_{0} r^{2} }$ .

And also the newton force will occur due to this force,

$F_{21}=ma$ .

Now equate the above two values of force will get,

$\frac{q^{2} }{4\pi\epsilon_{0} r^{2} } =ma$

Further solve this,

$q^{2}=ma4\pi \epsilon_{0} r^{2}$ .

Substitute all the known variables in above equation,

$q^{2}=(2.098\times 10^{-3} )(269.429)(4(3.14))(8.85\times 10^{-12})(3.338\times 10^{-2})$ .

$q=2.64\times 10^{-7} C$ .

6 0

3 years ago

Much power does a 10 Ohm bulb have in a series circuit with a battery of 12V and nothing else in the the circuit?￼￼

Much power does a 10 Ohm bulb have in a series circuit with a battery of 12V and nothing else in the the circuit?