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dlinn [17]
3 years ago
8

Cuál es el tiempo empleado por una moto que alcanza una velocidad final de 100km/h partiendo del reposo y lo hace a una acelerac

ión constante de 2km/h 2 ?
Physics
1 answer:
victus00 [196]3 years ago
6 0

Answer:

50 horas

Explanation:

Datos:

velocidad inicial: v_{i}=0km/h (inicia del reposo)

velocidad final: v_f=100km/h

aceleración: a=2km/h^2

Usando la formula de la velocidad final con aceleracion constante:

v_f=v_i+at

donde t es el tiempo.

De la formula anterior despejamos para el tiempo t:

t=\frac{v_f-v_i}{a}

sustituimos los valores:

t=\frac{100km/h-0km/h}{2km/h^2}\\ \\t=\frac{100km/h}{2km/h^2}\\ \\t=50h

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The crops will have the ability to be resistant to certain diseases

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A gas is collected from a radioactive material; upon inspection, the gas is identified as helium. the presence of the helium ind
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3 years ago
n deep space, sphere A of mass 47 kg is located at the origin of an x axis and sphere B of mass 110 kg is located on the axis at
Volgvan

Answer:

a)-1.014x 10^{-7J

b)3.296 x  10^{-7J

Explanation:

For Sphere A:

mass 'Ma'= 47kg

xa= 0

For sphere B:

mass 'Mb'= 110kg

xb=3.4m

a)the gravitational potential energy is given by

U_{i = -GMaMb/ d

U_{i= - 6.67 x 10^{-11} x 47 x 110/ 3.4 => -1.014x 10^{-7J

b) at d= 0.8m (3.4-2.6) and U_{i=-1.014x 10^{-7J

The sum of potential and kinetic energies must be conserved as the energy is conserved.

K_{i + U_{i= K_{f + U_{f

As sphere starts from rest and sphere A is fixed at its place, therefore K_{i is zero

U_{i= K_{f + U_{f

The final potential energy is

U_{f= - GMaMb/d

Solving for 'K_{f '

K_{f = U_{i + GMaMb/d => -1.014x 10^{-7 + 6.67 x 10^{-11} x 47 x 110/ 0.8

K_{f = 3.296 x  10^{-7J

6 0
2 years ago
What is the mass, in grams, of a pure iron cube that has a volume of 3.70cm cubed?
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To determine the amount in grams of the iron, we need data on the density of iron. From literature, it has a value of <span>p=7.9 g/cm3. We simply multiply the volume to the density. We do as follows:

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Hope this answers the question. Have a nice day.</span>
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3 years ago
How long does it take for a 3.5 kW electric water heater to heat 40 kg of water? from 20 ° C to 75 ° C? The specific heat capaci
iren [92.7K]

Answer:

2633.7 s

Explanation:

From the question,

Heat lost by the water heater = Heat gained by the water

Applying,

P = cm(t₂-t₁)/t.................. Equation 1

Where P = power of the heat, c = specific heat capacity of water, m = mass of water, t₁ = initial temperature, t₂ = final temperature, t = time

make t the subject of the equation

t = cm(t₂-t₁)/P.............. Equation 2

From the question,

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Substitute these values into equation 2

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t = 9218000/3500

t = 2633.7 s

4 0
2 years ago
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