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dlinn [17]
3 years ago
8

Cuál es el tiempo empleado por una moto que alcanza una velocidad final de 100km/h partiendo del reposo y lo hace a una acelerac

ión constante de 2km/h 2 ?
Physics
1 answer:
victus00 [196]3 years ago
6 0

Answer:

50 horas

Explanation:

Datos:

velocidad inicial: v_{i}=0km/h (inicia del reposo)

velocidad final: v_f=100km/h

aceleración: a=2km/h^2

Usando la formula de la velocidad final con aceleracion constante:

v_f=v_i+at

donde t es el tiempo.

De la formula anterior despejamos para el tiempo t:

t=\frac{v_f-v_i}{a}

sustituimos los valores:

t=\frac{100km/h-0km/h}{2km/h^2}\\ \\t=\frac{100km/h}{2km/h^2}\\ \\t=50h

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If the box weighs 40 newtons and is lifted a distance of 2 meters, how much work is done on the box?
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Answer:

The work done on the box is 80 J.

Explanation:

Given that,

Weight of box = 40 N

Distance = 2 meter

We need to calculate the work done

Using formula of work done

W=F\times x

W=mg\times x

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Put the value into the formula

W=40\times2

W= 80\ Nm

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Which term s the product of force and distance?
goldfiish [28.3K]

Answer:

The answer should be <u>WORK </u>

<em>(Hope this Helps)</em>

Explanation:

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8 0
3 years ago
Please Help!
irga5000 [103]

The maximum force that the tires can exert on the road before slipping is 16200 N.

From the information in the question;

The coefficient of static friction =  0.9

The mass of the car = 1800 kg

Using the formula;

μ = F/R

μ  = coefficient of static friction

F = force on the tires

R = the reaction force

But recall that the reaction is equal in magnitude to the weight of the car.

W=R

Hence; R = 1800 kg × 10 ms-2 = 18000 N

Making F the subject of the formula;

F = μR

Substituting values;

F =  18000 N × 0.9

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Learn more: brainly.com/question/18754989

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