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Stolb23 [73]
3 years ago
13

Si pudieras viajar a la Luna:

Physics
1 answer:
Nostrana [21]3 years ago
4 0

Answer:

i) Distancia, ii) La cinta métrica es impracticable.

Explanation:

i) El concepto físico que se construye únicamente del punto de salida y el punto de llegada a la Luna es el concepto de desplazamiento, definido como la distancia en línea recta de un punto en el espacio con respecto a un punto de referencia (la Tierra en este caso).

La distancia puede involucrar trayectorias curvilíneas entre los puntos mencionados.

ii) Por último, el uso de una cinta métrica es impracticable debido a la cantidad de material a utilizar y los efectos gravitacionales, electromagnéticos y mecánicos que inducen a una deflexión o una ruptura de esa cinta debido a la magnitud de la distancia entre las superficies del planeta y el satélite, respectivamente.

En este caso, es mejor utilizar la medición con tecnología láser, basadas en el fenómeno del electromagnetismo.

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You walk into a darkened room and turn on a flashlight. You see an image of the flashlight reflecting off a plane mirror in fron
user100 [1]

Answer:

4.2 is the answer

Explanation

The image formed in a plane mirror is an equal distance behind the mirror as the object in front of it.

Step 1: the equation to this problem would be: 8.4/2

Step 2: 8.4 ÷ 2 = 4.2

6 0
2 years ago
When applying a horizontal force of 30N, an object of mass 6 kg accelerates at 4m/s2. The force of friction on the surface must
Rus_ich [418]
Using Newton's Second Law, F = ma, where F is the net force

So the net force is:

F = (6kg)(4m/s^2) = 24N

Since you are applying a horizontal force of 30N, we can find the force of friction by the difference of the net force and the applied force.

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F_{f} = 6N
4 0
3 years ago
The more active a cell is, the more of these structures it has.
Aleks [24]

Answer:pretty sure its mitochondria

Explanation:

6 0
4 years ago
How to rearrange the formula f = ma and solve for m
GuDViN [60]
F /a = m


is the answer
7 0
3 years ago
Read 2 more answers
Charge of uniform density (0.30 nC/m2) is distributed over the xy plane, and charge of uniform density (−0.40 nC/m2) is distribu
soldier1979 [14.2K]

Answer: E = 39.54 N/C

Explanation: Electric field can be determined using surface charge density:

E = \frac{\sigma}{2\epsilon_{0}}

where:

σ is surface charge density

\epsilon_{0} is permitivitty of free space (\epsilon_{0} = 8.85.10^{-12}C^{2}/N.m^{2})

Calculating resulting electric field:

E=E_{1} - E_{2}

E = \frac{\sigma_{1}-\sigma_{2}}{2\epsilon_{0}}

E = \frac{[0.3-(-0.4)].10^{-9}}{2.8.85.10^{-12}}

E=0.03954.10^{3}

E = 39.54

The resulting Electric Field at any point is 39.54N/C.

8 0
3 years ago
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