Based on all we know about the terrestrial worlds, the single factor appears to play the most important role in a terrestrial planet's geological destiny is size size of terrestrial planet .
According to the question
Terrestrial Planets:
They belongs to a class of planets that are like the earth
Geological destiny :
Geology is biological destiny: Whatever minerals land or are deposited in a place determine what or who can make a living there millions of years later
Based on all we know about the terrestrial worlds, what single factor appears to play the most important role in a terrestrial planet's geological destiny
i.e
The size of terrestrial planet is one of the factors to play the most important role in a terrestrial planet's geological destiny
which determines how long the planet can retain internal heat, which drives geological activity because Smaller worlds cool off faster and harden earlier .
Hence, Based on all we know about the terrestrial worlds, the single factor appears to play the most important role in a terrestrial planet's geological destiny is size size of terrestrial planet .
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Answer:
Explanation:
If an object is moving, it is said to have kinetic energy (KE). Potential energy (PE) is energy that is "stored" because of the position and/or arrangement of the object. The classic example of potential energy is to pick up a brick. When it's on the ground, the brick had a certain amount of energy.
Cereals are usually fortified with three most common minerals and vitamins which are:
1- Iron
2- Vitamin D
3- Vitamin B-12
Comparing the above to the given choices, we will find that the best answer is:
b. iron
A.a sign that breaks loose from the ground when a force is applied to it
Answer:
113.85 m
Explanation:
When the car is on the pavement:
v₀ = 0 m/s
a = 5.75 m/s²
t = 4.4 s
Find: Δx and v
Δx = v₀ t + ½ at²
Δx = (0 m/s) (4.4 s) + ½ (5.75 m/s²) (4.4 s)²
Δx = 55.66 m
v = at + v₀
v = (5.75 m/s²) (4.4 s) + 0 m/s
v = 25.3 m/s
When the car is in the mud:
v₀ = 25.3 m/s
v = 0 m/s
a = -5.5 m/s²
Find: Δx
v² = v₀² + 2aΔx
(0 m/s)² = (25.3 m/s)² + 2 (-5.5 m/s²) Δx
Δx = 58.19 m
The total displacement is therefore:
55.66 m + 58.19 m = 113.85 m
