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tamaranim1 [39]
3 years ago
9

Find the value of the combination

Mathematics
1 answer:
scoray [572]3 years ago
6 0
=1 I calculated the combine value
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What are the possible values of x in -11x^2 + 2x = 10?
vlabodo [156]
        -11x² + 2x = 10
-11x² + 2x - 10 = 10 - 10
-11x² + 2x - 10 = 0
x = <u>-(2) +/- √((2)² - 4(-11)(-10))</u>
                     2(-11)
x = <u>-2 +/- √(4 - 440)</u>
               -22
x = <u>-2 +/- √(-436)
</u>             -22<u>
</u>x = <u>-2 +/- 2i√(109)
</u>              -22
x = <u>-2 + 2i√(109</u>)        x = <u>-2 - 2i√(109)</u>
             -22                            -22
x = ¹/₁₁ - ¹/₁₁i√(109)    x = ¹/₁₁ + ¹/₁₁i√(109)
<u />
8 0
3 years ago
Can someone please please help me on this algebra problem I’m stuck on answering the question?
Rudik [331]

Explanation:

Midline: it is a horizontal line where half of the function above it and half of the function is below it.

Amplitude: It means how far the function varies from the midline to the above and below.

Period: the distance between two consecutive maximum points (minimum points).

3) From the graph,

\begin{gathered} \text{Midline}=\frac{Maximum\text{ point+ minimum point}}{2} \\ =\frac{3+(-1)}{2} \\ =\frac{3-1}{2} \\ =\frac{2}{2} \\ =1 \end{gathered}

Answer: Midline=1

1) Amplitude

\text{Amplitude =}2

2) Periods

\begin{gathered} \text{Period}=6 \\ \Rightarrow b=\frac{2\pi}{6} \end{gathered}

4) The trigonometric equation is,

\begin{gathered} y=a\cos (b(x-c))+d \\ a=\text{ amplitude} \\ b=\text{period} \\ c=\text{ phase shift} \\ d=\text{ vertical shift} \\ y=2\cos (\frac{2\pi}{6}x)+1 \end{gathered}

Answer:

y=2\cos (\frac{2\pi}{6}x)+1

4 0
1 year ago
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