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Orlov [11]
3 years ago
13

Five wheels are connected as shown in the figure. Find the velocity of the block “Q”, if it is known that: RA= 5 [m], RB= 10 [m]

, RD= 6 [m], RE=12 [m]. ​

Physics
1 answer:
Tanzania [10]3 years ago
6 0

Answer:

-5 m/s

Explanation:

The linear velocity of B is equal and opposite the linear velocity of E.

vB = -vE

vB = -ωE rE

10 m/s = -ωE (12 m)

ωE = -0.833 rad/s

The angular velocity of E is the same as the angular velocity of D.

ωE = ωD

ωD = -0.833 rad/s

The linear velocity of Q is the same as the linear velocity of D.

vQ = vD

vQ = ωD rD

vQ = (-0.833 rad/s) (6 m)

vQ = -5 m/s

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OverLord2011 [107]

Answer:

The phase difference is       \Delta \phi = 1.9995 rad  

Explanation:

From the question we are told that

    The distance between the  loudspeakers is d = 2m

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     The frequency of the  loudspeakers is  f = 4450Hz

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           \Delta \phi =  \frac{2 \pi}{\lambda } *  \Delta z

Where \lambda is the wavelength which is mathematically represented as

          \lambda  = \frac{v_s }{f}

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          \lambda  = \frac{343 }{4450}

        \lambda  = 0.0770 m

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      \Delta \phi =  \frac{2 * 3.142 * 0.0245}{0.0770}

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