What is the frequency of radiation emitted by a photon of light if the energy released during its transition to ground state is
3.611 × 10-15 joules? (Planck's constant is 6.626 × 10-34 joule seconds)
1 answer:
Answer:
5.449 x 10¹⁸ Hz
Explanation:
Energy (E) =Frequency (F) x Plancks constant (h)
F= 3.611x10⁻¹⁵J / 6.626 x 10⁻³⁴ Js⁻¹
F =5.449 x10¹⁸ s⁻¹ or 5.449 x 10¹⁸ Hz
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