C)"his refusal to cooperate with the police and name the culprit...resulted in his arrest..."
To determine the concentration of one solution which is specifically basic or acidic solution through taking advantage on its points of equivalence, titration analysis is done.
Let us determine the reaction for the titration below:
2NaOH +2H2SO4 = Na2SO4 +2H2O
So,
0.0665 mol NaOH (2 mol H2SO4/ 2mol NaOH) / .025 L solution
= 2.62 M H2SO4
The answer is the fourth option:
<span>2.62 M</span>
Answer : The volume of
produced at standard conditions of temperature and pressure is 0.2422 L
Explanation :
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,

where,
= initial pressure of
gas = (740-22.4) torr = 717.6 torr
= final pressure of
gas at STP= 760 torr
= initial volume of
gas = 280 mL
= final volume of
gas at STP = ?
= initial temperature of
gas = 
= final temperature of
gas = 
Now put all the given values in the above equation, we get:


Therefore, the volume of
produced at standard conditions of temperature and pressure is 0.2422 L
Answer:
2Ag⁺ (aq) + 2OH⁻ (aq) → Ag₂O (s) + H₂O (l)
Explanation:
Step 1: RxN
2AgNO₃ + 2NaOH → Ag₂O + 2NaNO₃ + H₂O
Step 2: Define states of matter
2AgNO₃ (aq) + 2NaOH (aq) → Ag₂O (s) + 2NaNO₃ (aq) + H₂O (l)
Step 3: Total Ionic Equation
2Ag⁺ (aq) + 2NO₃⁻ (aq) + 2Na⁺ (aq) + 2OH⁻ (aq) → Ag₂O (s) + 2Na⁺ (aq) + 2NO₃⁻ (aq) + H₂O (l)
Step 4: Cancel out spectator ions
2Ag⁺ (aq) + 2OH⁻ (aq) → Ag₂O (s) + H₂O (l)
Find the number of moles
C = n / V
C(Concentration) = 0.30 moles / L
V ( Volume) = 2 L
n = ??
n = C * V
n = 0.30 mol / L * 2 L
n = 0.60 mol
Find the molar mass
2Na = 23 * 2 = 46 grams
1S = 32 * 1 = 32 grams
O4 = 16 * 4 = 64 grams
Total = 142 grams / mol
Find the mass
n = given mass / molar mass
n = 0.06 mol
molar Mass = 142 grams / mol
given mass = ???
given mass = molar mass * mols
given mass = 142 * 0.6
given mass = 85.2 grams.
85.2 are in a 2 L solution that has a concentration of 0.6 mol/L