Using the equation for boiling point elevation Δt Δt = i Kb m we can find the new boiling point T for the solution: Δt = T - 100∘C since we know that pure water boils at 100 °C.
We know that the van't Hoff Factor i is equal to 1 because sugar does not dissociate in water.
Also, the value of Ebullioscopic constant Kb for water is listed as 0.512 °C·kg/mol.
The molality m of the solution of 6 moles of sugar dissolved in a kilogram of water can be calculated as m = 6 moles / 1 kg = 6 mol/kg
Therefore the new boiling point T would be T - 100 °C = i Kb m T = i Kb m + 100 °C. = (1) (0.512 °C·kg/mol) (6 mol/kg) + 100 °C = 3.072 °C + 100 °C = 103.072 °C
A. The water will freeze. This is because if there's not enough heat, water will freeze. Just like in winter. There's not enough heat to keep the water from melting, so it just freezes. Hope this helps!
