Using the equation for boiling point elevation Δt Δt = i Kb m we can find the new boiling point T for the solution: Δt = T - 100∘C since we know that pure water boils at 100 °C.
We know that the van't Hoff Factor i is equal to 1 because sugar does not dissociate in water.
Also, the value of Ebullioscopic constant Kb for water is listed as 0.512 °C·kg/mol.
The molality m of the solution of 6 moles of sugar dissolved in a kilogram of water can be calculated as m = 6 moles / 1 kg = 6 mol/kg
Therefore the new boiling point T would be T - 100 °C = i Kb m T = i Kb m + 100 °C. = (1) (0.512 °C·kg/mol) (6 mol/kg) + 100 °C = 3.072 °C + 100 °C = 103.072 °C
