will tell you the subshell type, so you are dealing with a d orbital.
ml will tell you the orientation of the orbital, there is no distinction between the orbitals so -1 doesnt specifically mean anything.
Answer:
Explanation:
To solve this problem, we have to remember the ideal gas theory. We going to use the Gay Lussac Law.
The equation is:
PiTo = PoTi
Where:
<em>Pi =initial pressure</em>
<em>Po = final pressure</em>
<em>Ti = initial temperature</em>
<em>To = final temperature</em>
Let's use this equation and replace the values:
<em>Pi = 107 kPa</em>
<em>Ti = 22°C</em>
<em>To = 45 °C </em>
<em>Po = ? </em>
<em />
You can use the units as the problem gave you.
Using the Gay Lussac law:
107 kPa x 45 °C = Po x 22°C
Po = (4,815 kPa°C / 22°C) = 218.86 kPa
Po = 218 kPa
Answer:
The Percent composition of isopropanol in the mixture is 29.07 %
Explanation:
Step 1: Data given
Number of moles isopropanol (C3H8O) = 2.52 moles
Mass of the solution = 521 grams
Molar mass of isopropanol (C3H8O) = 60.1 g/mol
Step 2: Calculate mass of isopropanol
Mass isopropanol = moles isopropanol * molar mass isopropanol
Mass isopropanol = 2.52 moles * 60.1 g/mol
Mass isopropanol = 151.45 grams
Step 3: Calculate the percent composition of isopropanol in the mixture
Percent composition of isopropanol = (mass isopropanol / total mass of mixture) * 100 %
Percent composition of isopropanol = (151.45 grams / 521 grams ) * 100 %
Percent composition of isopropanol = 29.07 %
The Percent composition of isopropanol in the mixture is 29.07 %
Answer:
For 1 mole of Lead(II)chlorie we have 1 mole of lead (Pb), 2 moles of Chlorine (Cl) and 4 moles of oxygen (O).
Explanation:
<u>Step 1: </u>Data given
Number of moles of Pb(ClO2)2 = 1
Since the oxidation number of Pb is 2+ and the oxidation number of ClO2 is -1
So to bind we should have <u>twice</u> ClO2
1 mole of Pb(ClO2)2 contains 1 mole of Pb; 1*<u>2</u>= 2 moles of Cl and 2*<u>2</u> = 4 moles of 0.
This means for 1 mole of Lead(II)chlorie we have 1 mole of lead (Pb), 2 moles of Chlorine (Cl) and 4 moles of oxygen (O).
Answer:A) After the values are added, we determine how many significant figures are involved by looking at the decimal places of the original values. 52.13 had only 2 digits past the decimal point so the answer can only contain 2 significant numbers after the decimal point which would be 53.88 g
Explanation:
