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3 years ago

What materials are used on solar panels to allow them to produce electricity?

1 answer:

6 0

Rays of sunlight hit the solar panel and are
absorbed by semi-conducting materials such as silicon.
Photovoltaic cells are
usually made from silicon, an excess material that constitutes more
than 28 percent of the Earth's crust.
These cells are created by bonding two
wafers of silicon that are connected to metal wires
The top water is silicon is thin and bottom is thicker the wafers produce electricity as absorb solar radiation
hope it helps

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Which organisms play roles similar to organisms in water ecosystem

lina2011 [118]

Is there a multiple choice?

4 0

4 years ago

It took 50 joules to push a shopping cart 5 meters.with what face was the shopping cart pushed?

gladu [14]

Hello! So Ik this can be wrong but I worked hard for it(: It took 50 joules to push a shopping cart 5 meters with what force was the shopping cart pushed. blinded him to enable him and his men to escape. the answer is: round. Done!

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3 years ago

A mass of 100g stretches a spring 5cm. If the mass is set in motion from itsequilibrium position with a downward velocity of 10

stepladder [879]

Answer:

The required IVP is;

u'' + 196u = 0

where;

u(0) = 0 and

u'(0) = -10

Explanation:

See the attached for explanation

3 0

3 years ago

200 J of work is done when a force is applied to an object and the object moves 10 m to the right. How much Force was applied?

ArbitrLikvidat [17]

Answer:

20N

Explanation:

Given parameters:

Work done = 200J

Distance moved = 10m

Unknown:

Amount of force applied =?

Solution:

Work done is the force applied on a body to move it in the direction of the force.

Work done = force x distance

The unit of work done is in joules

Since the unknown is force, we make it the subject of the expression;

Force = $\frac{Work done}{distance}$

Force = $\frac{200}{10}$ = 20N

5 0

4 years ago

A spaceship maneuvering near planet zeta is located at r⃗ =(600i^−400j^+200k^)×103km, relative to the planet, and traveling at v

slava [35]

Answer:

The spaceship's position when the engine shuts off = $(708.15 i - 444.1 j + 200 k)*10^3km$

Explanation:

Initial location of spaceship = (600 i - 400 j + 200 k)* $10^3km$ = (600 i - 400 j + 200 k)* $10^6m$

Initial velocity = 9500 i m/s

Acceleration = (40 i - 20 k) $10^3m/s^2$

Time = 35 minute = 35 * 60 = 2100 seconds

We have equation of motion , $s= ut+\frac{1}{2} at^2$ , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

Substituting

$s= (9500 i)*2100+\frac{1}{2}*(40 i - 20 k)*2100^2\\ \\ s=9500*2100 i+20*2100^2i-10*2100^2j\\ \\ s=19.95*10^6i+88.2*10^6i-44.1*10^6j\\ \\ \\s=(108.15i-44.1j)*10^6m$

So final position = $((600 i - 400 j + 200 k)+(108.15i-44.1j))*10^6=(708.15 i - 444.1 j + 200 k)*10^6m$

= $(708.15 i - 444.1 j + 200 k)*10^3km$

The spaceship's position when the engine shuts off = $(708.15 i - 444.1 j + 200 k)*10^3km$

3 0

3 years ago

Read 2 more answers