Answer:
(a)The volume of the iron anchor = 25.2 m³
<em>(b)The mass of iron = 196812 kg</em>
Explanation:
<em>Density:</em> This is the ratio of the mass of a body to its volume. The S.I unit of density is <em>kg/m³</em>
(a)
From Archimedes principle, the iron will displace a volume of water that is equal to its volume. And the weight of water displaced is equal to loss in weight or upthrust.
Therefore, Upthrust = lost in weight = weight of water displace.
Therefore, Volume of the iron = mass of water displace/density of water
Vi = m₁/D₁........................... Equation 1
Where Vi = volume of iron, m₁ = mass of water displaced, D₁ = Density of water.
<em>Given: upthrust = 252 N, ∴ m₁ = 252/10 = 25.2 kg.</em>
<em>Constant: D₁ = 1.0 kg/m³</em>
<em>Substituting these values into equation 1,</em>
Vi = 25.2/1.0
Vi = 25.2 m³
Therefore the volume of the iron anchor = 25.2 m³
(b)
<em>Density of the iron = mass of the iron/volume of the iron.</em>
<em>Therefore, Mass of the iron = Density of the iron × volume of the iron...........................................equation 2</em>
<em>Given: Density of the iron = 7810 kg/m³, Volume of the iron = 25.2 m³</em>
<em>Substituting these values into equation 2,</em>
<em>Mass of the iron = 7810×25.2</em>
<em>Mass of the iron = 196812 kg.</em>
<em>Therefore the mass of iron = 196812 kg</em>
