Use the following half-life graph to answer the following question:
1 answer:
Answer:
A 1.0 min
Explanation:
The half-life of a radioisotope is defined as the time it takes for the mass of the isotope to halve compared to the initial value.
From the graph in the problem, we see that the initial mass of the isotope at time t=0 is
The half-life of the isotope is the time it takes for half the mass of the sample to decay, so it is the time t at which the mass will be halved:
We see that this occurs at t = 1.0 min, so the half-life of the isotope is exactly 1.0 min.
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Answer:
20N
Explanation:
Given parameters:
Work done = 200J
Distance moved = 10m
Unknown:
Amount of force applied =?
Solution:
Work done is the force applied on a body to move it in the direction of the force.
Work done = force x distance
The unit of work done is in joules
Since the unknown is force, we make it the subject of the expression;
Force =
Force = = 20N
Answer:
q = 224 mm, h ’= - 98 mm, real imagen
Explanation:
For this exercise let's use the constructor equation
where f is the focal length, p and q are the distance to the object and the image respectively.
In a mirror the focal length is
f = R / 2
indicate us radius of curvature is equal to the diameter of the eye
R = 3,50 10² mm
f = 3.50 10² /2 = 1.75 10² mm
they also say that the distance to the object is p = 0.800 10³ mm
1 / q = 1 / f - 1 / p
1 / q = 1 / 175 - 1 /800
1 / q = 0.004464
q = 224 mm
to calculate the size let's use the magnification ratio
m =
h '=
h ’= - 224 350 / 800
h ’= - 98 mm
in concave mirrors the image is real.
Answer:
a) 4.25 x 10∧-5 T
b) 16.03 mv
Explanation:
the solution is shown in the pictures attached
