Answer:
Explanation:
Power of defective eye = (1 / near point )+ (1 / lens-retina distance )
1 / .0198 m = (1 / near point )+ (1 / .02 m )
= 50.50 = (1 / near point )+ 50
0.50 = 1 / near point
near point = 1 / .5 = 2m
= 200 cm .
for near point at 25 cm , convex lens will be required.
u = - 25 cm , v = - 200 cm ,
1 / v - 1 / u = 1 /f for lens
- 1 / 200 + 1 / 25 = 1 / f
= .04 - .005 = 1 /f
.035 = 1 / f
f = 28.57 cm = 0.2857 m
power = 1 /f
= 1 / 0.2857
= 3.5 D .
i v ) option is correct .
Answer: D. 500 J
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Explanation:
To find the amount of work done, we multiply the force by displacement
work = force*displacement
work = (100 N)*(5 m)
work = (100*5) Nm
work = 500 J
In this case, "Nm" refers to "Newton meters" and not "nanometers"
1 newton meter is equal to 1 joule
D.transverse waves move perpendicular and longitudinal waves move parallel to the direction of energy movement..
Answer:
3 m/s squared
Explanation:
The formula you use is Vf= Vi + at. You rearrange it to a= Vf - Vi/t. The Vf is 27m/s. The Vi is 0m/s and the t is 9s. Cross out Vi since it’s zero and you’re left with a= 27m/s divided by 9s, which equals 3
