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Brilliant_brown [7]
3 years ago
11

1. What is the gravitational force of attraction between two 800 kg spherical objects that are 5 m apart? What would the gravita

tional force of attraction between these two objects be if the distance between them was changed to 10 m?
Physics
1 answer:
Katyanochek1 [597]3 years ago
4 0

Answer:

the force of gravity between them is quadrupled .

Explanation:

Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces.

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In a skate park, you are trying to determine how to get the most speed at the bottom of the ramp. If the ramp is 4.5 m high, and
Oksanka [162]

Answer:

If you have an initial velocity of 1.5m/s and the ramp height is 4.5, and an extreme fart is initiated at the bottom of the ramp exerting an didditional upward force, and the smell of the fart causes you to begin flailing, and everyone running from you causes an additional wind force, then you would be rolling at a speed of 3 m/s given there is no friction. :)

7 0
2 years ago
How can you put a lever into a rube goldberg machine? answer ASAP
Volgvan

Answer:

In our project, we have a class one lever that is hit by a pulley basket, thus letting a ball roll down.

Explanation:

7 0
3 years ago
Read 2 more answers
A satellite is orbiting Earth with a distance R = 2REarth from Earth's center. If the satellite is moved to a distance R = 4REar
Maslowich

Answer:

Half

Explanation:

Given that:

  • radial distance of satellite from the earth, R=2R_E

Now, if the satellite is moved to a distance R=4R_E

<u>We  have the mathematical expression for the potential energy fue to gravitational field as:</u>

U=\frac{G.M.m}{R} ...................(1)

where:

G = 6.67\times 10^{-11}\ m^3.kg^{-1}.s^{2}

M = mass of earth

m = mass of satellite

R = radial distance of satellite

<u>Now from eq. (1) initially we have:</u>

U=\frac{G.M.m}{2R_E}

<u>after the satellite is moved, we have:</u>

U'=\frac{G.M.m}{4R_E}

\Rightarrow U'=\frac{G.M.m}{2(2R_E)}

\Rightarrow U'=\frac{1}{2} \times U

which is half of the initial condition.

3 0
3 years ago
Generate description of the right hand rule for finding the magnetic field around a current carrying wire an tell how it is used
vladimir1956 [14]

Answer:

Right hand thumb rule : It is a rule used to find the magnetic field direction around current carrying wire .

Explanation:

It states that : "If you grasp conductor in your right hand such that thumb points in upward direction ,then the direction in which our finger curls gives the direction of magnetic field or magnetic lines of forces" .

This rule proves that :Current can give rise to magnetism .

Around every current carrying conductor there exist a magnetic field which can be easily felt .

According to this rule : When a current flows in upward direction ,the finger curls in anticlockwise direction and when direction of current reverses ,then the direction of field also reverses .

4 0
3 years ago
How many joules of heat must be transferred to a 410-g aluminum pizza pan to raise its temperature from 32oC to 232oC? The speci
xxTIMURxx [149]

Answer:

recall that heat absorbed released is given by

Q = mc*(T2 - T1)

where

m = mass (in g)

c = specific heat capacity (in J/g-k)

T = temperature (in C or K)

*note: Q is (+) when heat is absorbed and (-) when heat is released.

substituting,

Q = (480)*(0.97)*(234 - 22)

Q = 98707 J = 98.7 kJ

Explanation:

3 0
3 years ago
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