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Vlad1618 [11]
3 years ago
5

Which diagram represents an element that is likely to form covalent bonds?

Physics
2 answers:
Serhud [2]3 years ago
7 0

Answer:

The second option

Explanation:

The octet rule states that elements tend to bond in such a way that each atom has eight electrons in its valence (outermost) shell, except for the first level which is complete with 2 electrons.

The first picture shows an atom with only 1 electron in its valence shell, the second picture 5 electrons, the third pictures 8 electrons and the fourth picture 2 electrons. The first and last cases are more likely to lose their valence electrons to form bonds than share them into a covalent bond (because they are few). The third case has the octet rule already satisfied, so is not likely to neither lose/receive nor share its electrons. The atom of the second case can share 3 electrons to complete the octet rule.

ankoles [38]3 years ago
3 0

Answer:

Ok look Im going try my best, and the answer that most likely looks like it can be correct is C the third picture i hope this is correct and helps bye bye:3

also do you wanna get some points >w>

Explanation:

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Que es un kilogramo fuerza.?
Kipish [7]
El kilogramo de fuerza, o kilopond, es una unidad de fuerza métrica gravitacional. Es igual a la magnitud de la fuerza ejercida sobre un kilogramo de masa en un campo gravitatorio de 9.80665 m / s².
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3 years ago
What type of tissue in the heart pumps blood throughout the body?
slavikrds [6]

Answer:

Myocardium. That is the type. (srry i was in a rush hope this helps)

7 0
3 years ago
In which stage of a star's life cycle, does gravity and fusion become balanced, and an adult star forms?
V125BC [204]

Answer:

im guessing red giant-

8 0
3 years ago
Give the number of significant figures: 832.000 km
Galina-37 [17]
It has three significant figure
8 0
4 years ago
If the coefficient of friction is 0.3900 and the cylinder has a radius of 2.700 m, what is the minimum angular speed of the cyli
Aleks04 [339]

Answer:

w=3.05 rad/s or 29.88rpm

Explanation:

k = coefficient of friction = 0.3900

R = radius of the cylinder = 2.7m

V = linear speed of rotation of the cylinder

w = angular speed = V/R or to rewrite V = w*R

N = normal force to cylinder

N==\frac{m(V)^{2}}{R}=m*(w)^2*R

Friction force\\Ff = k*N\\Ff= k*m*w^2*R

Gravitational force \\Fg = m*g

These must be balanced (the net force on the people will be 0) so set them equal to each other.

Fg = Ff

m*g = k*m*w^2*R

g=k*w^{2}*R

w^2 =\frac{g}{k*R}

w=\sqrt{\frac{g}{k*R}} \\w =\sqrt{\frac{9.8\frac{m}{s^{2}}}{0.3900*2.7m}}\\ w=\sqrt{9.306}=3.05 \frac{rad}{s}

There are 2*pi radians in 1 revolution so:

RPM=\frac{w}{2\pi }*60\\RPM=\frac{3.05\frac{rad}{s}}{2\pi}*60\\RPM= 0.498*60\\RPM=29.88

So you need about 30 RPM to keep people from falling out the bottom

7 0
4 years ago
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