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Svet_ta [14]
3 years ago
5

If a student tried to lift a 350 N box upwards with a lever that is 75 cm long, how much force would they need to provide given

a fulcrum 20 cm away from the box. 1312.5 N. 93.3 N. 65.6N. 2333N.
Physics
2 answers:
Lana71 [14]3 years ago
7 0

Answer:

93.3 N

Explanation:

Applying the equation of moment

M = r * F

r = distance from the applied force to the object = 75 cm

F = force applied = X

Moment of force = load * distance from load = 350 * 20

back to equation

350 * 20 = X * 75

7000 = 75 X

X ( force applied/needed) = 7000 / 75 = 93.3 N

Radda [10]3 years ago
3 0

We will take moment about the fulcrum point

Taking, box 350 N at a distance of  20 cm

we can write the moment equation as below:

350 N x 20 cm - X x 75 cm = 0

X = 350 N x 20 cm /75 cm

= 93.33 N



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Answer:

Speed of the wreckage = 49.29 km/hr

Explanation:

This question is solved simply by using the conservation of momentum law.

The momentum of the three moving bodies are calculated below:

Momentum of Car 1 : 1100 * 55 = 60500 kg.km/hr

Momentum of Truck : 480 * 37 = 17760 kg.km/hr

Momentum of Car 2 : 1300 * 49 = 63700 kg.km/hr

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The final momentum equals the initial momentum if it is conserved. Thus we have the following equation:

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If you transfer equal amounts of geat to 1kg of water and 1kg of cooper, the temperature of the cooper will change more . . . it'll get more degrees warmer than the water will.

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Answer:

m = 44~Kg

Explanation:

<u>Net Force</u>

Newton's second law explains the dynamics principles when a number of forces are applied to an object.

The net force vector is the sum of the individual vector forces applied. The magnitude of the net force is related to the magnitude of the acceleration of the body as follows:

Fn=m.a

Furthermore, the acceleration can be calculated if we know the kinematic behavior of the body:

\displaystyle a=\frac{v_f-v_o}{t}

Where vf, vo, and t are the final speed, initial speed, and time, respectively.

The box is pushed across the floor with a force of 25 N against a frictional force of 14 N.

The net force applied to the box is:

Fn = 25 N - 14 N = 11 N

We also know the box is accelerated from rest (vo=0) to vf=4 m/s in t=16 seconds, thus:

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a = 0.25~m/s^2

From the equation:

Fn=m.a

We solve for m:

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Answer: The angle between the two colours when they emerge is 0.4°

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