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Sphinxa [80]
3 years ago
13

What effects do coil of wire on a compass after it has been connected to a battery​

Physics
1 answer:
Yanka [14]3 years ago
8 0

Explanation:

The compass needle moved when the wire was connected to the battery. The important point here is that the needle is affected by the wire only when both ends of the wire are connected to the battery because only at this time is current flowing through the circuit.

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________ is an arrhythmia in which there is a very fast but regular rhythm (250 beats per minute) of the atria or ventricles.
erastova [34]

Answer:

Flutter

Explanation:

Flutter is a type of arrhythmia that causes very fast and regular ryth of the atria of about 250 beats per minute.

Arrhythmia can be defined as any sort of irregularity heart rate or rhythm is also called as dysrhythmia.

Arrhythmias can be categorized as heart block, bradycardia, tachycardia, fibrillation, flutter, sick sinus syndrome, and is diagnosed by Electrocardiography.

In Flutter, the heart chambers do get sufficient time to get filled with blood completely prior to next contraction.

4 0
3 years ago
What are the similarities & differences between a thermistor and a light dependent resistor in physics?
viva [34]

An LDR's resistance changes with light intensity, while a thermistor's resistancce changes with temperature.

In dark, LDR's resistance is large and in the day/light LDR's resistance is small.

At low temperature, thermistor's resistance is large, while at large temperature it resistance is small.

In an LDR Resistance increases as light intensity falls, while in a thermistor resistance falls as temperature falls.

5 0
3 years ago
Through what angle in degrees does a 33 rpm vinyl record turn in 0.23 s : A) 46° B) 26° C) 53° D) 33°
solniwko [45]

Answer:

(a) angle record will be 46°

Explanation:

We have given speed = 33 rpm

Time t = 0.23 sec

We know that 1 revolution = 360°

And 1 minute = 60 sec

So 33 revolution/minute \frac{33\times 360}{60}=198^{\circ}/sec

So angle record by vinyl =198\times 0.23=45.54^{\circ} , which is nearly equal to 46

So angle record by vinyl is 46°

So option (a) will be the correct answer

5 0
3 years ago
A horizontal spring-mass system has low friction, spring stiffness 165 N/m, and mass 0.6 kg. The system is released with an init
AURORKA [14]

a) 19.4 cm

b) 3.2 m/s

Explanation:

a)

A horizontal spring-mass system has a motion called simple harmonic motion, in which the mass oscillates following a periodic function (sine or cosine) around an equilibrium position.

As the system oscillates back and forth, its total mechanical energy (sum of elastic potential energy and kinetic energy) will remain conserved (since we consider friction negligible). The elastic potential energy at any point is given by:

U=\frac{1}{2}kx^2

where

k is the spring constant

x is the displacement of the system

While the kinetic energy at any point is

K=\frac{1}{2}mv^2

where

m is the mass

v is the speed

So the total mechanical energy of the system is

E=K+U=\frac{1}{2}mv^2+\frac{1}{2}kx^2

For this system, when it is initially released,

m = 0.6 kg

k = 165 N/m

x = 7 cm = 0.07 m

v = 3 m/s

So the total energy is

E=\frac{1}{2}(0.6)(3)^2+\frac{1}{2}(165)(0.07)^2=3.1 J

Since friction is negligible, this total energy remains constant. Therefore, when the system reaches its maximum stretch during the motion, the kinetic energy will be zero and all the mechanical energy will be elastic potential energy; so we will have:

E=U=\frac{1}{2}kx_{max}^2

where x_{max} is the maximum stretch. Solving for x_{max},

x_{max}=\sqrt{\frac{2E}{k}}=\sqrt{\frac{2(3.1)}{165}}=0.194 m

So, 19.4 cm.

b)

The maximum speed in a spring-mass oscillating system is reached when the kinetic energy is maximum, and therefore, since the total energy is conserved, when the elastic potential energy is zero:

U=0

which means when the displacement is zero:

x = 0

So, when the system is transiting through the equilibrium position.

Therefore, the total mechanical energy is equal to the maximum kinetic energy:

E=K=\frac{1}{2}mv_{max}^2

where

m is the mass

v_{max} is the maximum speed

Here we have:

E = 3.1 J

m = 0.6 kg

Therefore, solving for the maximum speed,

v_{max}=\sqrt{\frac{2E}{m}}=\sqrt{\frac{2(3.1)}{0.6}}=3.2 m/s

6 0
3 years ago
In a close system a gas with constant volume at 20C and pressure
jonny [76]

Answer:

6bar

Explanation:

According to pressure law;

P1/T1 = P2/T2

Given the following;

P1 = 1bar

T1  = 20oC

P2 = ?

T2 = 120oC

Substitute

1/20 = P2/120

20P2 = 120

P2 = 120/20

P2 = 6bar

Hence the new pressure will be 6bar

4 0
3 years ago
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