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3 years ago

Que es el periodo de un pendulo

Physics

2 answers:

Akimi4 [234]3 years ago

4 0

Answer:

what

Explanation:

Ipatiy [6.2K]3 years ago

4 0

Answer:

El periodo del péndulo simple, para oscilaciones de poca amplitud, viene determinado por la longitud del mismo y la gravedad.

Explanation:

No influye la masa del cuerpo que oscila ni la amplitud de la oscilación. Donde: T: Periodo del péndulo.

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A dog of mass 18 kg runs at a speed of 4 m/s. What is the momentum of the

Andrej [43]

Answer:

A, 72 kg•m/s

Explanation:

p=mv

p=18x4

p=72

6 0

4 years ago

A car is moving at 14 m/s. After 30 s, its speed inncreased to 20 m/s. What is the acceleration over time

Juli2301 [7.4K]

Answer:

0.2 m/s^2

Explanation:

initial speed 14m/s

final speed 20m/s

acceleration:

(20m/s - 14m /s) /30s = (6m/s)/30s = 0.2 m/s^2

7 0

3 years ago

On a very hot summer day, the rooms on the first floor of a house stay cooler than the rooms on the second. Which form of therma

saw5 [17]

Answer:

Convection causes warm air in your living space to rise. That air moves by conduction through the ceiling to the attic floor .

5 0

4 years ago

The electric field inside a cell membrane is 8.0 MN/C. Part A What's the force on a singly charged ion in this field?

dlinn [17]

Answer:

Force on the singly charged ion will be $12.6\times 10^{-13}N$

Explanation:

We have given electric field E = 8 MN/C

So electric field in N/C will be $E=8MN/C=8\times 10^6N/C$

It is given that ion so charge on ion will be equal to $e=1.6\times 10^{-19}C$

We have to find the electric force on the ion

Electric force is equal to $F=qE$ , here q is charge and E is electric field

So force on the charge will be equal to $F=8\times 10^6\times 1.6\times 10^{-19}=12.6\times 10^{-13}N$

So force on the singly charged ion will be $12.6\times 10^{-13}N$

7 0

4 years ago

We are given a piece of copper of mass m=0.82 g to form a cylindrical wire of resistance R=0.87.2. What should be the length / o

Genrish500 [490]

Answer:

Length of wire=2.16 m

Diameter of wire=0.232 mm

Explanation:

m= mass of copper wire= 0.82 g

R= Resistance of copper wire= 0.87 ohms

D= Density of copper= 8.96 g/cm^3

ρ= Resistivity= 1.7×10^-8 Ωm

$Density=\frac{mass}{volume}\\\Rightarrow volume=\frac{mass}{density}\\\Rightarrow volume=\frac {0.82}{8.96}\\\Rightarrow volume=0.091\ cm^3\\ volume = \pi r^2 l\\\Rightarrow \pi r^2=\frac{volume}{l}\\ \Rightarrow \pi r^2=\frac {0.091}{l}\\$

$\rho=R\frac{A}{l}\\\Rightarrow 1.7\times 10^{-8}=0.87 \frac{\pi r^2}{l}\\\Rightarrow 1.7\times 10^{-8}=0.87 \frac{0.091\times 10^{-6}}{l^2}\\\Rightarrow l^2=\frac {0.87\times 0.091\times 10^{-6}}{1.7\times 10^{-8}}\\\Rightarrow l^2=0.046\times 10^2\\\Rightarrow length=2.16\ m$

$\pi r^2=\frac {0.091}{l}\\\Rightarrow r^2=\frac {0.091\times 10^{-6}}{2.16 \pi}\\\Rightarrow r^2=1.34\times 10^{-8}\\\Rightarrow r=0.00011\ m\\\Rightarrow d=0.000232\ m\\\therefore diameter=0.232\ mm$

3 0

3 years ago