To solve this we are going to use the formula for ideal mechanical advantage:
where
is the machine mechanical advantage
is the input distance
is the output distance
We know for our problem that
and
. Lets replace those values in our formula to find
:
The ideal machine advantage of the machine is 3. The inventor is claiming that the actual mechanical advantage of the machine is 4. Since the actual mechanical advantage takes into account energy losses, it is always less than the ideal mechanical advantage.
We can conclude that the developer's claim is false.
The prediction should the expect to occur will be C₂ attracts B₂. This is due to the fact that like charges repel while the unlike charges attract each other.
<h3>What is a magnet?</h3>
A magnet is an iron piece or of other material with its constituent atoms arranged in such a way that it shows magnetism qualities,
Like charge attracting different iron-containing objects or engaging itself in a magnetic field.
The given metallic bars are A, B, and C. Every end of the magnet is denoted with the 1 and 2.
The denotation to the magnet is given as;
A₁A₂
B₁B₂
C₁C₂
He places the end of one bar close to an end of a second bar. The end of magnets C₂ and B₂ are of unlike charges. As we know that the unlike charges attract each other.
So that the C₂ and B₂ due to the unlike charge ends attract each other.
Hence the prediction should the expected to occur will be C₂ attracts B₂
To learn more about the magnet refer to the link;
brainly.com/question/13026686
Answer:
The starting height of the ball is approximately 0.604 m
Explanation:
The given parameters are;
The mass of the the ball = 0.050
The speed with which it travels through the top loop = 2 m/s
The given height at which the ball moves at 2 m/s = 0.40 m
Therefore, we have;
1/2·m·v² = m·g·h
1/2·v² = g·h
h = 1/2·v²/g = 1/2 × 2²/9.81 ≈ 0.204
The additional height = h = 0.204 m
Therefore;
The starting height of the ball ≈ The given height at which the ball moves at 2 m/s + h
The starting height of the ball ≈ 0.40 + 0.204 = 0.604 m
The starting height of the ball ≈ 0.604 m.