Explanation:
u=166m/s, v=0(at it's highest point final velocity is zero), a=9.8m/s², t=8.6s
by the formula, S=ut+½at².
S=[166×8.6+½.×9.8×(8.6)²]. ...by calculation
S = 1427.6+362.404
S=1790.004m
hope this helps you.
The heat energy the surrounding air gained is <u>755 j.</u>
Energy is a quantitative property given to a body or physical system and can be identified as work being done in the form of heat and light. Energy is Conserved - The law of conservation of energy states that energy can be transformed into form, but cannot be created or destroyed. Energy is the ability to do work. It can exist in electrical, kinetic, thermal, electrical, chemical, nuclear, or other forms.
<u>Concept:-</u>
Since the energy is always conserved, the energy lost by the hot water is gained bt the surrounding
- energy lost = + energy gained by the surrounding
- 755 j = + <u>755 j</u>
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Energy exists in many forms. Examples include light energy, thermal energy, mechanical energy, gravitational energy, electrical energy, acoustic energy, chemical energy, and nuclear or atomic energy. Each form can be transformed or changed into other forms.
Learn more about energy here:-brainly.com/question/13881533
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Explanation:
The force is 186.5 N. 3.8% of the force is directed downward. So the vertical component of the force is:
Fᵧ = 0.038 (186.5 N)
Fᵧ = 7.087 N
The horizontal component is found with Pythagorean theorem:
F² = Fₓ² + Fᵧ²
(186.5 N)² = Fₓ² + (7.087 N)²
Fₓ = 186.4 N
So the work done is:
W = Fd
W = (186.4 N) (7.4 m)
W = 1379 J
Round as needed.
The volumetric rate or flow rate of a fluid is defined as the amount of the volume of a fluid circulating on a surface per unit of time. In this case we have units given initially: Gallons and minutes. For the first part we will convert the minutes to seconds, and we will obtain the flow rate under that measure. For the second case we will convert the gallons to cubic meters and obtain the desired value. Recall the following conversion rates,
If the flow rate is defined as the volume by time, the flow rate with the given values is
PART A ) Converting to Gal/seconds, we have,
PART B) Converting Gal/seconds to 
