Answer:
The speed of the car before it began to skid is 47.56 m/s.
Explanation:
We can use kinematics to solve this problem.
We are given three known variables:
- Δx = 290 m
- a = -3.90 m/s²
- v = 0 m/s (final velocity is 0 m/s because the car skids to a stop).
We can use this kinematic equation to <u><em>solve</em></u><em> for the initial velocity</em>, v₀.
Substitute the known variables into the equation.
- (0)² = v₀² + 2(-3.9)(290)
- 0 = v₀² - 2262
- 2262 = v₀²
- <u>v₀ = 47.56 m/s</u>
The speed of the car before it began to skid is 47.46 m/s.
Answer:
According to the second law of thermodynamics, we are unable to use the heat of the ocean and the atmosphere because we do not have a reservoir that has a temperature lower than the ocean or the atmosphere.
Explanation:
As you already know, the ocean and atmosphere have a lot of thermal energy, however, we are unable to convert this energy into mechanical energy that would be useful for our activities. This can be explained by the second law of thermodynamics, since it states that the presence of two bodies with different temperatures is necessary for it to be possible to transform heat into work.
In this case, to transform the thermal energy of the ocean and the atmosphere into mechanical energy we would need the existence of a thermal motor, which is only possible to be established when there is a body with high thermal energy and a sink, a reservoir, with low thermal energy, which will be the place where the heat will be expelled, to be converted into work. We do not have a reservoir with less thermal energy than the ocean and the atmosphere, so we cannot use their energy.
Answer:
230.4 N
Explanation:
From the question given above, the following data were obtained:
Charge (q) of each protons = 1.6×10¯¹⁹ C
Distance apart (r) = 1×10¯¹⁵ m
Force (F) =?
NOTE: Electric constant (K) = 9×10⁹ Nm²/C²
The force exerted can be obtained as follow:
F = Kq₁q₂ / r²
F = 9×10⁹ × (1.6×10¯¹⁹)² / (1×10¯¹⁵)²
F = 9×10⁹ × 2.56×10¯³⁸ / 1×10¯³⁰
F = 2.304×10¯²⁸ / 1×10¯³⁰
F = 230.4 N
Therefore, the force exerted is 230.4 N
I believe it is away from his arm since the question states his arm is applying an upwards force
