Answer:
The amount of cargo the plane can carry is 8707.89 N
Explanation:
The surface area of the wings facing the air = 30×6×2 × sin(2.5) = 15.7 m²
The speed of the plane 550 km/h = 152.78 m/s
The volume of air cut through per second = 15.7 × 152.78 = 2399.07 m³
The mass of air = Volume × Density = 2399.07 × 0.37 = 887.65 kg
Weight of air = Mass × Acceleration due to gravity = 887.65 × 9.81 = 8707.89 N
Given that the plane is already airborne, the additional cargo the plane can carry is given by the available lift force of the plane.
The amount of cargo the plane can carry = 8707.89 N
Answer:
Fatigue factor of safety is 2.0267
Explanation:
Solution is attached below.
Answer:
The correct option is;
Terminate
Explanation:
Termination of the risk is equivalent to elimination of the risk by avoiding the activity that brings about the risk or by using a different process that does not include the risk observed in the previous process option
When the reward far outweigh the risk, it may be decided to terminate or eliminate the risk and miss the reward and also terminate the likelihood of the losses to be incurred.
Answer:
A
Explanation:
The best method that will yield significantly more accurate result is to use spectrophotometer to read the turbidity of the sample and increase in turbidity is associated with increase biomass.
