Question 40 and the next Question 41

You are to design two CONCEPTUALLY different synchronous state machines (Mealy and Moore) that perform the task described below.

allochka39001 [22]

Answer:

Explanation:

I hope this helps!

3 0

3 years ago

In a manufacturing facility, 2-in-diameter brass balls (k = 64.1 Btu/h·ft·°F, rho = 532 lbm/ft^3, and cp = 0.092 Btu/lbm·°F) ini

bekas [8.4K]

Answer:

Explanation:

First we compute the characteristic length and the Biot number to see if the lumped parameter

analysis is applicable.

Since the Biot number is less than 0.1, we can use the lumped parameter analysis. In such an

analysis, the time to reach a certain temperature is given by the following

From the data in the problem we can compute the parameter, b, and then compute the time for

the ratio (T – T)/(Ti

– T)

4 0

3 years ago

Read 2 more answers

A NC drill press is to perform a series of through-hole drilling operations on a 1.75 in thick aluminum plate that is a componen

jekas [21]

Answer:

26.7 min

Explanation:

First, we will find the time required to drill each hole:

N = 300 x 12/0.75 $\pi$ = 1527.7 rev/min

fr = 1527.7 (0.015) = 22.916 in/min

Formula for distance per hole: 0.5 + A + 1.75

A = 0.5 (0.75) tan (90-100 / 2) = 0.315 in
Tm = (0.5 + 0.315 + 1.75) / 22.916 = 0.112 min

Now, we will calculate the time required to draw back the drill form hole:

= 0.112 / 2 = 0.056 min

Time to move between holes = 1.5 / 15 = 0.1 min

For 100 holes, the number of moves between holes = 99

Total time required to drill 100 holes (t):

t = 100 (0.112 + 0.056) + 99 (0.1) = 26.7 min

7 0

3 years ago

Read 2 more answers

Air enters a turbine operating at steady state at 440 K, 20 bar, with a mass flow rate of 6 kg/s, and exits at 290 K, 5 bar. The

marysya [2.9K]

Answer:

The rate of heat transfer is - 935.392 kW

Explanation:

Given;

inlet pressure, P₁ = 20 bar

inlet temperature, T₁ = 440 k

outlet pressure, P₂ = 5 bar

outlet temperature, T₂ = 290 k

inlet velocity, v₁ = 18 m/s

outlet velocity, v₂ = 30 m/s

mass flow rate, Q = 6kg/s

developed power, W = 815 kW

From steam table;

at P₁ and T₁, interpolating between T = 400 and T = 450, h₁ = 3335.52 kJ/kg

at P₂ and T₂, interpolating between T= 250 and T= 300, h₂ = 3043.5 kJ/kg

Applying steady state energy balance equation;

$\frac{Q}{m} -\frac{W}{m} = h_2-h_1 +\frac{1}{2} (v_2{^2} -v_1{^2})\\\\\frac{Q}{m} = h_2-h_1 +\frac{1}{2} (v_2{^2} -v_1{^2}) +\frac{W}{m}$

substitute values above into this equation and evaluate the rate of heat transfer

$\frac{Q}{m} = h_2-h_1 +\frac{1}{2} (v_2{^2} -v_1{^2}) +\frac{W}{m}\\\\\frac{Q}{m} = 3043.5 - 3335.52 +\frac{1}{2000} (30{^2} -18{^2}) + \frac{815}{m} \\\\\frac{Q}{m} = -291.732 + \frac{815}{m}\\\\\frac{Q}{m} = \frac{815}{m} -291.732\\\\Q = 815 - m(291.732)\\Q = 815 - 6*291.732\\\\Q = 815-1750.392 = -935.392 \ kW$

Therefore, the rate of heat transfer, in kW, for a control volume enclosing the turbine is - 935.392 kW

4 0

3 years ago

Which of these include some basic characteristics of taxi services? (Select all that apply.)Transactions are often negotiated at

Nezavi [6.7K]

Answer:j

Explanation:

6 0

2 years ago