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3 years ago

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One of the laws of conservation states that the total charge of the reactants and products must be equal. This is the law of con

servation of: A. energy. B. matter. C. energy and matter. D. charge.

1 answer:

const2013 [10]3 years ago

6 0

D, you wanna know why.... cause I looked it up

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An electric car has a battery that can hold 16 kwh of energy. if the battery is designed to operate at 340 v, how many coulombs

Zanzabum

charge needed= 169412 C

Explanation:

energy stored in the battery= 16 KWh= 16 (1000 W)(3600 s)= 5.76 x 10⁷ J

Energy stored is given by U= q V

q= charge

V= voltage= 340 V

so 5.76 x 10⁷ = q (340)

q= 169412 C

4 0

4 years ago

4. Two people each have a mass of 55 kg. They are both in an

mestny [16]

Answer:

350 N

Explanation:

F=ma

$f = force \\ m = mass \\ a = acceleration$

$m = 2(55kg) + 240kg \\ a = 1.0 \frac{m}{ {s}^{2} }$

Force = 350 Newtons

4 0

3 years ago

A proton is released from rest at the origin in a uniform electric field that is directed in the positive x direction with magni

Vika [28.1K]

Explanation:

It is given that,

Electric field, $E=950\ N/C$

We need to find the change in the electric potential energy of the proton-field system when the proton travels to x = 2.5 m

From the conservation of energy, the loss in potential energy is equal to the gain in kinetic energy and kinetic energy is is equal to the work done.

$W=F\times x$

$W=q\times E\times x$

$W=1.6\times 10^{-19}\times 950\times 2.5$

$W=3.8\times 10^{-16}\ J$

So, the change in electric potential energy of the proton field system is $3.8\times 10^{-16}\ J$ . Hence, this is the required solution.

4 0

3 years ago

Hello i need answers for this question, i need it asap, thanks!! i will give brainlist ☺️

nalin [4]

When frequency increases more wave crests pass a fixed point each second. That means the wavelength shortens. So, as frequency increases, wavelength decreases. The opposite is also true—as frequency decreases, wavelength increases.

5 0

3 years ago

1. What is the wave speed of a wave that has a frequency of 100 Hz and a wavelength of 0.30 m?

aivan3 [116]

Answer:

1. v = 30 m/s

2. v = 5 m/s

3. f = 40 Hz

4. f = 400 Hz

5. f = 300 Hz

6. λ = 0.772 m

7. λ = 0.386 m

8. λ = 0.625 m

9. v = 100 m/s

10. v = 50 m/s

Explanation:

The relationship between frequency, wavelength, and speed of a wave is given by the following formula:

$v = f\lambda$

where,

v = speed of wave

f = frequency of wave

λ = wavelength

1.

f = 100 Hz

λ = 0.3 m

Therefore,

v = (100 Hz)(0.3 m)

<u>v = 30 m/s</u>

<u></u>

2.

f = 50 Hz

λ = 0.1 m

v = (50 Hz)(0.1 m)

<u>v = 5 m/s</u>

<u></u>

3.

v = 20 m/s

λ = 0.5 m

$f = \frac{v}{\lambda} = \frac{20\ m/s}{0.5\ m}$

<u>f = 40 Hz</u>

<u></u>

4.

v = 80 m/s

λ = 0.2 m

$f = \frac{v}{\lambda}=\frac{80\ m/s}{0.2\ m}$

<u>f = 400 Hz</u>

<u></u>

5.

v = 120 m/s

λ = 0.4 m

$f = \frac{v}{\lambda}=\frac{120\ m/s}{0.4\ m}$

<u>f = 300 Hz</u>

<u></u>

6.

v = 340 m/s

f = 440 Hz

$\lambda = \frac{v}{f}=\frac{340\ m/s}{440\ Hz}\\$

<u>λ = 0.772 m</u>

<u></u>

7.

v = 340 m/s

f = 880 Hz

$\lambda = \frac{v}{f}=\frac{340\ m/s}{880\ Hz}\\$

<u>λ = 0.386 m</u>

<u></u>

<u></u>

8.

v = 250 m/s

f = 400 Hz

$\lambda = \frac{v}{f}=\frac{250\ m/s}{400\ Hz}\\$

<u>λ = 0.625 m</u>

<u></u>

9.

f = 50 Hz

λ = 2 m

v = (50 Hz)(2 m)

<u>v = 100 m/s</u>

<u></u>

10.

f = 100 Hz

λ = 0.5 m

v = (100 Hz)(0.5 m)

<u>v = 50 m/s</u>

6 0

3 years ago