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faltersainse [42]
3 years ago
7

True or False:

Physics
1 answer:
bulgar [2K]3 years ago
8 0

Answer:

False

True

True

True

True

False

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How does the loneliest whale relate to physics/waves.
Lelechka [254]
Answer: the loneliest whale relates to the communication that whales give to each other

Explanation: whales have different forms of communication , and the ‘loneliest’ whale can’t get any company by the other whales.


In other words: it may be a new and different way whales communicate, nobody knows much about the loneliest whale. It may be forming a new kind of communication
6 0
3 years ago
One of the foci for the moon's orbit would be the
suter [353]
The question is oversimplified, and pretty sloppy.

Relative to the Earth . . .
The Moon is in an elliptical orbit around us, with a period of
27.32... days, and with the Earth at one focus of the ellipse.

Relative to the Sun . . .
The Moon is in an elliptical orbit around the Sun, with a period
of 365.24... days, and with the Sun at one focus of the ellipse,
and the Moon itself makes little dimples or squiggles in its orbit
on account of the gravitational influence of the nearby Earth.

I'm sorry if that seems complicated.  You know that motion is
always relative to something, and the solar system is not simple.
5 0
2 years ago
Read 2 more answers
Alkaline batteries have the advantage of putting out constant voltage until very nearly the end of their life. How long will an
Sidana [21]

Answer:

Explanation:

Voltage, V = 1.58 V

Power, P = 1 W

1 A.h

Charge, Q = 1 A.h = 1 x 3600 A.s = 3600 C

Power x time = Voltage x charge

1 x t = 1.58 x 3600

t = 1.58 x 3600 second

t = 1.58 hours

8 0
3 years ago
If the period of a wave is 0.05 s, then what is its frequency?
yKpoI14uk [10]
Frequency = 1/time period = 1/0.05 = 20s^-1. 
8 0
3 years ago
Read 2 more answers
Atomic physicists usually ignore the effect of gravity within an atom. To see why, we may calculate and compare the magnitude of
STatiana [176]

Answer:

2.27\cdot 10^{49}

Explanation:

The gravitational force between the proton and the electron is given by

F_G=G\frac{m_p m_e}{r^2}

where

G is the gravitational constant

m_p is the proton mass

m_e is the electron mass

r = 3 m is the distance between the proton and the electron

Substituting numbers into the equation,

F_G=(6.67259\cdot 10^{-11} m^3 kg s^{-2})\frac{(1.67262\cdot 10^{-27}kg) (9.10939\cdot 10^{-31}kg)}{(3 m)^2}=1.13\cdot 10^{-68}N

The electrical force between the proton and the electron is given by

F_E=k\frac{q_p q_e}{r^2}

where

k is the Coulomb constant

q_p = q_e = q is the elementary charge (charge of the proton and of the electron)

r = 3 m is the distance between the proton and the electron

Substituting numbers into the equation,

F_E=(8.98755\cdot 10^9 Nm^2 C^{-2})\frac{(1.602\cdot 10^{-19}C)^2}{(3 m)^2}=2.56\cdot 10^{-19}N

So, the ratio of the electrical force to the gravitational force is

\frac{F_E}{F_G}=\frac{2.56\cdot 10^{-19} N}{1.13\cdot 10^{-68}N}=2.27\cdot 10^{49}

So, we see that the electrical force is much larger than the gravitational force.

5 0
3 years ago
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