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Schach [20]
3 years ago
5

Select the statement that correctly completes the description of phase difference.

Physics
1 answer:
KengaRu [80]3 years ago
3 0

Answer:

The difference in the phase angle between any two waves at any given position along the waves.

Explanation:

Phase difference describes  the difference in the phase angle between any two waves at any given position along the waves. The equation of wave is given by :

Wave 1, y=A\ sin(\omega t)

Wave 2, y=A\ sin(\omega t+\phi)

Where

A is the amplitude of wave

\omega is the angular frequency

\phi is the phase difference between two waves

If \Delta d is the path difference, it is given by :

\Delta d=d\ sin\theta

Hence, the correct option is (a) "the difference in the phase angle between any two waves at any given position along the waves".

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Because of various events in their (unknown) past history that resulted in deviations from the theoretical orbit. That formed in the plain of the ecliptic.

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3 years ago
What increase in temperature is needed to increase the length of an aluminum meterstick by 1.0 mm?
Fudgin [204]

Answer:

42k

Explanation:

4 0
2 years ago
A rock hits a window and stops in 0.15 seconds. The net force on the rock is 58N during the collision. What is the magnitude of
nlexa [21]

Answer:

The change in momentum is  \Delta p =   0.7 \ kg\cdot m \cdot s^{-1}

Explanation:

From the question we are told that

    The time taken for the stone to stop is \Delta  t = 0.15 \ seconds

    The net force on the rock is  F =  58 \ N

   

The impulse of the rock can be mathematically represented as

     I  =  F * \Delta t

Substituting values

     I  =  58 * 0.15

    I  =  0.7\  kg * m  * s^{-1}

Now impulse is defined as  the rate at which momentum change

   Hence the change in momentum \Delta p  of the rock is equal to the impulse of the rock

 So  

       \Delta p =  I  =  0.7 \ kg\cdot m \cdot s^{-1}

7 0
3 years ago
CALCULATE: find the velocity of a wave in a wave pool if it's wavelength is 3.2 m and its frequency is 0.60 Hz
vampirchik [111]
Number 2 ( 1.3m/s) good luck!
6 0
2 years ago
Read 2 more answers
Determine the image distance and image height for a 5.00 cm tall object placed 30.0 cm from a double convex lens with a focal le
vlabodo [156]

Answer:

The image distance is 30 cm

image height = - 5 cm

Explanation:

The formula for calculating the image distance is expressed as

1/f = 1/u + 1/v

where

f is the focal length

u is the object distance

v is the image distance

From the information given,

u = 30

f = 15

By substituting these values into the formula,

1/15 = 1/30 + 1/v

1/v = 1/15 - 1/30 = (2 - 1)/30 = 1/30

Taking the reciprocal of both sides,

v = 30

The image distance is 30 cm

magnification = image height/object height = - v/u

Given that object height = 5 cm, then

image height/5 = - 30/30 = - 1

image height = - 5 * 1

image height = - 5 cm

8 0
1 year ago
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