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Sonja [21]
3 years ago
9

Liquid ammonia (boiling point = –33.4°C) can be used as a refrigerant and heat transfer fluid. How much energy is needed to heat

25.0 g of NH3(l) from –65.0°C to –12.0°C?
Physics
1 answer:
Contact [7]3 years ago
6 0

Answer:

39.4 kJ

Explanation:

Given mass = 25.0 g

Specific heat of ammonia (g) = 4.7 J/g.K

Specific heat of ammonia (l) = 2.2 J /g.K

ΔHvap  = 23.5 x 10³ J /mol

Heating liquid ammonia from -65 °C to -33.4°C

Q₁ = m s ΔT  =  = 25.0 g * 4.7 J/g.K * [-33.4 - (-65)] °C = 3713 J

Evaporating 25 g of ammonia at -33.4°C

Molar mass of ammonia = 17 g/mol

Thus, moles = 25 / 17 moles

Q₂ = (25 / 17) mol * ΔHvap   = 1.470 mol * 23.5 x 10³ J /mol  = 34558.8 J

Heating NH₃(g) from -33.4°C  to -12.0°C

Q₃ = m s ΔT  =  = 25.0 g * 2.2 J/g.K * [-12.0 - (-33.4)] °C = 1177 J    

<u>Total heat energy = Q₁ + Q₂ +Q₃  = 39448.8 J  = 39.4 kJ (As 1 J = 10⁻³ kJ)</u>

                                 

                                   

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Delvig [45]

Hey! I empathize with you, as I just started the energy unit in physics as well!

Alright, lets list what we know, and which equation(s) we need.

PE = Gravitational Potential Energy

PEg = mgh

m = mass

g = gravity (9.8 m/s^2)

h = height

Guess what?

We need to find the height!

Lets make this more organized:

Known:

m = 40 kg

PE = 14000

g = 9.8 m/s^2

Unknown:

h = ?

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Now, if we take a look at the equation PEg = mgh, you will see that we have everything besides the height! So lets solve for the height by substituting in for the variables we know:

14000 J = 40 kg * (9.8 m/s^2) * h

40 * 9.8 = 392  

14000 J = 392 * h

14000/392 = h

35.71 m = h

There we go! If you simply list what you know and don't know, you will find the equation you need to solve the problem.

Have a great day and good luck!

7 0
3 years ago
the momentum of a spring coil when the external compressing force is removed b the difference between the final momentum and the
Fed [463]

Answer:

the correct one is b

the difference between the final moment and the initial moment

Explanation:

The momentum is related to the moment

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          ∫ F dt = p_f - p₀

where p_f and p₀ are the final and initial moments, respectively

When checking the different answers, the correct one is b

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7 0
3 years ago
A sledgehammer strikes an anvil with a velocity of 50 ft/sec (Fig. 2.59). The hammer and the anvil weigh 12 lb and 100 lb, respe
saveliy_v [14]
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4 0
2 years ago
A hot-air balloon and its basket are accelerating upward at 0.265 m/s2, propelled by a net upward force of 688 N. A rope of negl
Sergeu [11.5K]

Question:<em> </em><em>Find, separately, them mass of the balloon and the basket (incidentally, most of the balloon's mass is air)</em>

Answer:

The mass of the balloon is 2295 kg, and the mass of the basket is 301 kg.

Explanation:

Let us call the mass of the balloon m_1 and the mass of the basket m_2, then according to newton's second law:

(1). \:F = (m_1+m_2)a,

where a =0.265m/s^2 is the upward acceleration, and F = 688N is the net propelling force (counts the gravitational force).

Also, the tension T in the rope is 79.8 N more than the basket's weight; therefore,

(2). \:T = m_2g+79.8

and this tension must equal

T -m_2g =m_2a

(3). \:T = m_2g +m_2a

Combining equations (2) and (3) we get:

m_2a = 79.8

since a =0.265m/s^2, we have

\boxed{m_2 = 301.13kg}

Putting this into equation (1) and substituting the numerical values of F and a, we get:

688N = (m_1+301.13kg)(0.265m/s^2)

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Thus, the mass of the balloon and the basket is  2295 kg and 301 kg respectively.

8 0
3 years ago
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bezimeni [28]

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F = ma

The force exerted on the charge by the electric field of intensity (E) is given by

F = Eq

Thus

Eq = ma

a = E * q/ m

Where a = acceleration of charge

E = strength of electric field = 7400N/c

q = magnitude of electronic charge = 1.609 * 10^-6c

m = mass of an electronic charge = 9.109 * 10^-31kg

a = 7400 * 1.609 * 10^-16/ 9.109 * 10^-31

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a = 1.19 * 10^-12 / 9.019 * 10^-31

a = 0.132 * 10^19

a = 1.32 * 10^18m/s²

As stated in the question, the direction of the electric field is due north hence, the direction of it force will also be north thus making the electron experience a force due north ( according to Newton second law of motion)

5 0
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