Answer:
saiffjyrkieijdyc digit both of dvur is the answer rcjcufi
Answer:
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Molality is the number of moles of solutes in 1 kg of solvent.
the molality of solution to be prepared is 2.0 molal.
therefore 2 moles in 1 kg water.
the mass of Li₂S required is - 46 g/mol x 2.0 mol = 92 g
the mass in 1 kg of solvent is - 92 g
Therefore mass of Li₂S required in 1600.0 g is - 92 g/kg x 1.6 kg = 147.2 g
Answer:
I'm pretty sure the answer is C.
The answer will be 3 moles
