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Leokris [45]
4 years ago
13

Why are some isotopes used as tracers?

Chemistry
2 answers:
Svetach [21]4 years ago
5 0

Answer:

the correct answer is D. They are uniquely identifiable like fingerprints.

~batmans wife dun dun dun....

Molodets [167]4 years ago
3 0

Answer is C.

They decay at a predictable rate. IE carbon 14 decay to carbon 12 to understand how long ago something was alive.wer:

Explanation:

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The density of silver is 10.5 g/cm3. what would be the mass (in grams) of a piece of silver that occupies a volume of 23.6 cm3?
Keith_Richards [23]
Hey there : !

density = 10.5 g/cm³

volume = 23.6 cm³

therefore:

D = m / V

10.5 = m / 23.6

m = 10.5 * 23.6

m = 247.8 g

hope this helps!
6 0
3 years ago
Read 2 more answers
How much energy, in joules, does 150.0 g of water with an initial temperature of 25 C need to absorb be raised to a final temper
satela [25.4K]

Answer:

31395 J

Explanation:

Given data:

mass of water = 150 g

Initial temperature = 25 °C

Final temperature = 75 °C

Energy absorbed = ?

Solution:

Formula:

q = m . c . ΔT

we know that specific heat of water is 4.186 J/g.°C

ΔT = final temperature - initial temperature

ΔT = 75 °C - 25 °C

ΔT = 50 °C

now we will put the values in formula

q = m . c . ΔT

q = 150 g × 4.186 J/g.°C × 50 °C

q = 31395 J

so, 150 g of water need to absorb 31395 J of energy to raise the temperature from 25°C to 75 °C .

5 0
3 years ago
Which equation would you use to solve the following problem? An object is moved 29 meters with a force of 289 N. What is the wor
notsponge [240]

Work done can be calculated from force and distance the object moves.

The equation relating work done, force and distance is,

Work (Joules) = Force (Newton) * Distance (m)

Given the force acting on the object = 289 N

Distance the object moves = 29 m

Calculating the work done from force and distance:

Work = Force * Distance

= 289 N * 29 m

= 8381 J

= 8381 J * \frac{1 kJ}{1000 J} = 8.381 kJ

4 0
3 years ago
How the size of the sun compares to the sizes of the other stars
s2008m [1.1K]
Donut flavor apple sauce with chicken strips
5 0
3 years ago
Read 2 more answers
A galvanic cell consists of one half-cell that contains Ag(s) and Ag+(aq), and one half-cell that contains Cu(s) and Cu2+(aq). W
Agata [3.3K]

Answer : The 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

Explanation :

Galvanic cell : It is defined as a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy. It is also known as the voltaic cell or electrochemical cell.

In the galvanic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.

We are taking the value of standard reduction potential form the standard table.

E^0_{[Ag^{+}/Ag]}=+0.80V

E^0_{[Cu^{2+}/Cu]}=+0.34V

In this cell, the component that has lower standard reduction potential gets oxidized and that is added to the anode electrode. The second forms the cathode electrode.

The balanced two-half reactions will be,

Oxidation half reaction (Anode) : Cu(s)\rightarrow Cu^{2+}(aq)+2e^-

Reduction half reaction (Cathode) : Ag^{+}(aq)+e^-\rightarrow Ag(s)

Thus the overall reaction will be,

Cu(s)+2Ag^{+}(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)

From this we conclude that, 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

Hence, the 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

7 0
4 years ago
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